Suppose that h(x) = 4x – 5 and h(b) = 17. What is the value

QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! The ratio of the hours the Teenage Mutant Ninja Turtles spend training,

kicyunya [14]

Answer:

6 hours

The difference between the ratio numbers is 8-3 = 5. That corresponds to the 10-hour difference between training hours and pizza-eating hours. Thus, each ratio unit stands for 2 hours. The 3 ratio units spent eating pizza stand for ...

3×2 hours = 6 hours eating pizza

Step-by-step explanation:Hopefully this helped, if not HMU and I will get u a better answer!

and get i get brainliest plz, im trying to upgrade my statis

3 0

2 years ago

Choose the best statement that explains the graph represented by these ordered pairs.

Vlad [161]

Answer:

I wish you the best of luck you are strong and loved you are very smart happy holidays love you may god bless you

Step-by-step explanation:

7 0

3 years ago

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75 is what percent of 60

VLD [36.1K]

75 is 125% of 60. Hope this helps! :)

7 0

3 years ago

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

So

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

There is 1000cm3 of aluminum available to cast a trophy that will be in the shape of a right square pyramid. Is this enough alum

stealth61 [152]

The 1000 cubic centimeters of aluminium is enough for aluminium a trophy that will be in the shape of a right square pyramid and has a base edge of 10 cm and a slant height of 13 cm.

Step-by-step explanation:

The given is,

Volume of aluminium available is 1000 cubic centimeters

Shape of trophy is right square pyramid

Trophy has a base edge of 10 cm and slant height of 13 cm

Step:1

Formula for volume of right square pyramid,

$Volume, V = a^{2}\frac{h}{3}$ .....................................(1)

Where, a - Base edge value

h - Height of pyramid

From given,

a = 10 cm

h = 13 cm

Equation (1) becomes,

$= 10^{2}(\frac{13}{3} )$

$= (100)(4.333)$

$= 433.33 cm^{3}$

Volume of trophy = 433.33 cubic centimeters

Compare with the volume of available aluminium and volume of right square pyramid,

$Volume of available aluminium > Volume of right square pyramid$

$1000 cm^{3} > 433.33 cm^{3}$

So, the given volume of aluminium is enough to make right square pyramid shaped trophy.

Result:

The 1000 cubic centimeters of aluminium is enough for aluminium a trophy that will be in the shape of a right square pyramid and has a base edge of 10 cm and a slant height of 13 cm.

6 0

3 years ago

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