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pishuonlain [190]
3 years ago
7

Scientists discovered a large star 500,000 light-years from Earth. A light-year is about 5,880,000,000,000 miles. What is the di

stance of the large star from Earth in scientific notation?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0

7.35×10ⁿ13 im pretty sure this is corrext


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The length of a rectangle is four times its width.
Anna11 [10]

Answer:

Step-by-step explanation:

Area of a rectangle is given by:

           ....[1]

where

l is the length

w is the width of the rectangle respectively.

As per the statement:

the length of a rectangle is four times its width.

⇒

It is also given that: area of rectangle is 1024 cm square

Substitute the given values in [1] we have;

⇒

Divide both sides by 4 we have;

or

Taking square root both sides we have;

cm

Therefore, the width of the rectangle is, 16 cm

4 0
4 years ago
There is a 15% discount on all items in a store. You buy a $12 shirt and $45 jeans. What will be your total cost?
Nina [5.8K]

Answer:

The total cost of the shirt and Jean's together with a 15% discount would be $48.45.

Step-by-step explanation:

if you at 12 and 45 you get 57 now if you multiply that by .15 which would be 15% you would get $48.45.

6 0
3 years ago
Read 2 more answers
Help me out, thank you.
AveGali [126]

Answer: 38

Step-by-step explanation:

7 0
3 years ago
What is the exact area of a circle with a diameter of 64 m?
torisob [31]
The answer would be 45
5 0
3 years ago
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Solve: 10 2/3+2h≤4 1/3
PtichkaEL [24]

Answer:

\large\boxed{h\leq-\dfrac{19}{6}\to h\in\left(-\infty,\ -\dfrac{19}{6}\right]}

Step-by-step explanation:

\text{First convert the mixed numbers to the improper fractions:}\\\\10\dfrac{2}{3}=\dfrac{10\cdot3+2}{3}=\dfrac{32}{3}\\\\4\dfrac{1}{3}=\dfrac{4\cdot3+1}{3}=\dfrac{13}{3}\\\\\text{Solve the inequality}\\\\10\dfrac{2}{3}+2h\leq4\dfrac{1}{3}\\\\\dfrac{32}{3}+2h\leq\dfrac{13}{3}\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{32}{3\!\!\!\!\diagup_1}+3\cdot2h\leq3\!\!\!\!\diagup^1\cdot\dfrac{13}{3\!\!\!\!\diagup_1}\\\\32+6h\leq13\qquad\text{subtract 32 from both sides}\\\\6h\leq-19\qquad\text{divide both sides by 6}\\\\h\leq-\dfrac{19}{6}

6 0
3 years ago
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