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Marat540 [252]
3 years ago
6

What is the value of x in the rhombus below?

Mathematics
2 answers:
beks73 [17]3 years ago
8 0
3x+2+4x-10=180\\
7x=188\\
x\approx27


lara [203]3 years ago
4 0
The diagonals of a rhombus bisect<span> each other at </span>right angles (90°) and in a triangle, the three interior angles always add to 180°  ⇒

3x + 2 + 4x - 10 + 90 = 180
7x + 82 = 180
7x = 180 - 82
7x = 98
x = 98/7
x = 14
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Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

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Discarding, we have:

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Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

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16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
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