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cluponka [151]
3 years ago
10

PLEASE HELP ME ASP! Brainlist and 25 points!

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

Answer is in the explanation

Step-by-step explanation:

I don't know exactly word from word what your choices look like...

but I can describe per each box what happened in my own words:

First box:  They multiply first equation by 3 and the second equation by 2 to obtain the equations in that first box.

Second box: They subtracted the two equations in the first box to obtain 1x+0y=2 which means 1x=2 or x=2 (this is called solving a system by elimination

Third box: They used their first original equation (before the multiplication manipulation) and plug in the value they got for x which was 2 giving them 3(2)-2y=10

Fourth box: They simplified the equation 3(2)-2y=10 by performing the multiplication 3(2) giving them 6-2y=10

Fifth box:  They subtracted 6 on both sides giving them -2y=4

Sixth box:  They divided both sides by -2 giving them y=-2

I will summarize then what I wrote above:

1st box: Multiplication Property of Equality

2nd box: Elimination

3rd box: Substitution (plug in)

4th box: Simplifying

5th box:  Subtraction Property of Equality

6th box: Division Property of Equality

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Alex rode 15.5343 miles in his bike

Step-by-step explanation:

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4 years ago
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A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo
never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that \pi = 0.08

98% confidence level

So \alpha = 0.02, z is the value of Z that has a p-value of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}

0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}

\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2

n = 996.3

Rounding up:

A sample of 997 is needed.

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