Answer:
The value of x is 3.
Step-by-step explanation:
Matthew earned 7500 of 15000, which is exactly half the total amount, meaning that the fraction corresponding to his earnings is 1/2.
Rate of 5:2:x, with number 5 corresponding to Matthew, mean that his fraction of the earnings, in function of x is given by:

Both fractions are equal, so:

Applying cross multiplication:



The value of x is 3.
Answer:
B.) $58
Step-by-step explanation:
350-89-18-27-38-120 = 58
Answer:
Therefore, the probability is P=1/84.
Step-by-step explanation:
We have a bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty.
We conclude that in a bag have 9 tokens.
We calculate the probability that the red tokens are drawn consecutively.
We calculate the number of possible combinations:

Number of favorable combinations is 1.
Therefore, the probability is P=1/84.
Answer:
Area or parallelogram = base * height
Area = 9 units * 2/3 units
Area = 9/1 * 2/3 square units
Area = 18/3 square units
Area = 6 square units
Answer: area = 6 square units
Answer:
The first answer is correct.
Step-by-step explanation:
Line 5 says that the reason is due to substitution
Line 3 says m∠ SQT equals 180°
If we substitute 180° into the spot for m∠ SQT in line 4, we get solution option 1