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3 years ago

Someone help im so confused T-T

Mathematics

2 answers:

Svetlanka [38]3 years ago

6 0

Answer:First one which is the question mark on screamers is 4 and the second one which is the question mark under runners is 15

Daniel [21]3 years ago

4 0

Answer:

Step-by-step explanation: i think it would be 13,14 or maybe 10,6 if those aren't right let me know and i will give you another answer ok

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HELPPPP!!!!

Artist 52 [7]

Answer:

2000(1+5/100)^12 = 3591.712652

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3 years ago

Mrs. Harrison borrows $600 to pay for a new phone. the simple intrest on the loan is 9% for one year

laila [671]

Answer:

$600

Step-by-step explanation:

8 0

4 years ago

Fully simplify using only positive exponents.<br> 8x²y<br> x7y5

Bingel [31]

Answer:sorry can't answer that :(

8 0

3 years ago

SOMEONE PLEASE HELP ME

notka56 [123]

Area of deck= 2(20w)+4(w^2)+2(50w)d
456=2(20w)+4(w^2)+2(50w)

456=40w+4w^2+100w

456=4w^2+140w

114=w^2+35w

0=w^2+35w-114

find what 2 numbers multiply to get 114 and add to get 35 and factor

-3 and 38

0=(w-3)(w+38)

set each to zero

w-3=0

w=3

3 0

3 years ago

A fair spinner has 11 equal sections: 3 red, 4 blue and 4 green. It is spun twice. What is the probability of getting the same c

Aliun [14]

Answer:

The probability of getting the same colour twice is approximately 34%.

Step-by-step explanation:

The probability of getting each color is:

P(x=red) = 3/11
P(x=blue) = 4/11
P(x=green) = 4/11

Then, we can calculate the probability of getting the color red twice as:

$P(x_1=R;x_2=R)=P(x=R)^2=(3/11)^2=9/121$

We have to repeat this for the color blue and green:

$P(x_1=B;x_2=B)=P(x=B)^2=(4/11)^2=16/121\\\\P(x_1=G;x_2=G)=P(x=G)^2=(4/11)^2=16/121$

Then, the probability of getting the same color twice in two spins can be calculated as:

$P=P(x_1=R;x_2=R)+P(x_1=B;x_2=B)+P(x_1=G;x_2=G)=\\\\P=9/121+16/121+16/121\\\\P=41/121\approx0.34$

4 0

3 years ago