<h3><u>Question:</u></h3>
Juan and raj cut up a banana to put on cereal. juan puts 1/7 of the banana on his bowl of cereal, and raj puts 2/5 of the banana on his bowl of cereal.
what fraction of the banana did juan and raj put on their cereal altogether?
a. 2/35 banana
b. 3/12 banana
c. 3/7 banana
d. 19/35 banana
<h3><u>Answer:</u></h3>
Juan and Raj altogether put 19/35 banana
<h3><u>Solution</u>:</h3>
Given that, Juan and Raj cut up a banana to put on cereal
We have to find the fraction of banana put by Juan and Raj altogether
This means, we have to add both the fractions
Thus they put 
of banana by Juan and Raj altogether
I think it is 4 because it’s how many times it crosses the x axis
Answer:
sum = -15h+2
Step-by-step explanation:
Step-by-step explanation:
2x + 3y = 6
3y = -2x + 6
divide through by 3
y = (-2/3)x + 6............1
but equation of a straight line is
y = mx + c..............2
compare equation 1&2, m = -2/3 and c = 6
where m = gradient
c = intercept
Answer:
The meet at first time at starting point after 336 seconds,
Vanu have completed 7 laps while Tanuj has completed 6 laps.
Step-by-step explanation:
Given that Venu and Tanuj take 48 seconds and 56 seconds to
complete a lap respectively.
To meet them again at the startiong point, the time taken must be multiple of 56 and 48.
So, the minimum time required to meet them again at the startiong point is time taken for first time meet.
Time taken to first time meet is the smallest number which can be divided by 56 and 48, i.e the lowest common factor (LCM) of 56 and 48 which is 336 seconds or 5 minutes 36 seconds.
Number of laps by Venu
Number of laps by Tanuj
