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Len [333]
3 years ago
15

If there are 22 successes in a sample with a size of 40, what is the sample

Mathematics
2 answers:
patriot [66]3 years ago
3 0

Answer:

A

Step-by-step explanation:

22 successes out of a group of 40 means 22/40 were good. Now, simplify 22/40. Both can be divided by 2.

22/2 = 11

40/2 = 20

Now you have 11/20. Put this in decimal form and you have 0.55

enot [183]3 years ago
3 0

Answer: .55

A P E X

Step-by-step explanation:

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The kings ship sank with 8 gold bars aboard. The king paid Captain Nemo 4/5 of one bar for finding the gold. The Captain gave 1/
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4/5×1/2= 2/5. If you want your answer in decimal form than it would be 0.4.
4 0
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Find the other endpoint of the line segment with the given endpoint and midpoint.
Vlad1618 [11]

Answer:

(19,-14)

Step-by-step explanation:

let endpoint 2 be x2,y2

then apply mid point formula

x=(x1+x2)/2

y=(y1+y2)/2

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3 years ago
Keshawn left his house at time zero and drove for 4 minutes to the store, at a speed of 1 blocks per minute. Then he stopped and
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Step-by-step explanation:

6 0
3 years ago
A tennis ball in the shape or a sphere has a diameter of 6.7 centimeters which is closest to the volume
Lynna [10]
In your question it seems like there should be choices too! Either way, how does one find the volume of a sphere?
8 0
2 years ago
se quiere pintar una pared en forma de hexágono regular y se sabe que cada lado mide 3m y que su apotema es de 2,8m cual es el a
qwelly [4]

Answer:

El área total a pintar será:

A_{tot}=25.2\: m^{2}

Step-by-step explanation:

Sabiendo el apotema y la longitu de los lados, podemos encontrar el área de un triangulo. Recordemos que, si trazamos rectas del centro del hexágono a los vértices, se formaran 6 triángulos equiláteros.

El área de un triángulo es:

A_{t1}=\frac{b*a}{2}

b es la longitud de la base (b=3 m)

a es la apotema, osea la altura del triangulo (a = 2.8)

A_{t1}=\frac{2.8*3}{2}

A_{t1}=4.2\: m^{2}

Ahora, solo debemos mutiplicar ese valor por 6 para determianr el área total de la pared.

A_{tot}=25.2\: m^{2}

Espero te haya sido util!

5 0
3 years ago
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