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Len [333]
3 years ago
15

If there are 22 successes in a sample with a size of 40, what is the sample

Mathematics
2 answers:
patriot [66]3 years ago
3 0

Answer:

A

Step-by-step explanation:

22 successes out of a group of 40 means 22/40 were good. Now, simplify 22/40. Both can be divided by 2.

22/2 = 11

40/2 = 20

Now you have 11/20. Put this in decimal form and you have 0.55

enot [183]3 years ago
3 0

Answer: .55

A P E X

Step-by-step explanation:

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The figure shows the layout of a symmetrical pool in a water park. What is the area of this pool rounded to the tens place? Use
k0ka [10]

Answer:

2489ft^{2}

Step-by-step explanation:

The pool are is divided into 4 separated shapes: 2 circular sections and 2 isosceles triangles. Basically, to calculate the whole area, we need to find the area of each section. Due to its symmetry, both triangles are equal, and both circular sections are also the same, so it would be enough to calculate 1 circular section and 1 triangle, then multiply it by 2.

<h3>Area of each triangle:</h3>

From the figure, we know that <em>b = 20ft </em>and <em>h = 25ft. </em>So, the area would be:

A_{t}=\frac{b.h}{2}=\frac{(20ft)(25ft)}{2}=250ft^{2}

<h3>Area of each circular section:</h3>

From the figure, we know that \alpha =2.21 radians and the radius is R=30ft. So, the are would be calculated with this formula:

A_{cs}=\frac{\pi R^{2}\alpha}{360\°}

Replacing all values:

A_{cs}=\frac{(3.14)(30ft)^{2}(2.21radians)}{6.28radians}

Remember that 360\°=6.28radians

Therefore, A_{cs}=994.5ft^{2}

Now, the total are of the figure is:

A_{total}=2A_{t}+2A{cs}=2(250ft^{2} )+2(994.5ft^{2})\\A_{total}=500ft^{2} + 1989ft^{2}=2489ft^{2}

Therefore the area of the symmetrical pool is 2489ft^{2}

3 0
3 years ago
A utility company’s pump moves 1,008 gallons of water in 8 minutes. What is the unit rate in gallons per minute
Anit [1.1K]

Answer:

126 gallons per minute

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
For every 45 vehicles up past 15 are many vans so how many minivans would pass if there were 60 vehicles
Colt1911 [192]
The case is about proportional relatioship so to slove it you have to do this.
45(V)       ?
____  x  ____
60(V)      15

45*15=675
60*?=60
675 DIVIDE BY 60=11.25
so the answer is 11.25
hope it help you
thank you
:)
7 0
3 years ago
The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15
katrin [286]
<h2>Hello!</h2>

The answer is: The first graphic representation.

<h2>Why?</h2>

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

h(t)=-16.1t^2 + 150\\0=-16.1t^2 + 150\\16.1t^2=150\\t^2=\frac{150}{16.1}=9.32\\t=+-\sqrt{9.32}=+-3.05\\t1=3.05\\t2=-305

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

a=-1\\b=0\\c=150

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

8 0
3 years ago
Read 2 more answers
. Mrs. Khan makes cookies for the school bake sale. She uses the equation c = 0.75x to determine the cost, c, for x cookies. Whi
IRINA_888 [86]

Answer:

The answer is D.

Step-by-step explanation:

3 0
3 years ago
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