1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rus_ich [418]
3 years ago
6

Triangle ABC is similar to triangle DBE.

Mathematics
1 answer:
allsm [11]3 years ago
3 0

Answer:

Step-by-step explanation:

You might be interested in
Find cos y and tan y if csc y = -√6/2 and cot y >0.
fomenos

Answer:

\cos y = -\dfrac{\sqrt{3}  }{3}

\tan y = \sqrt{2}

Step-by-step explanation:

Recall that

\boxed{\csc y := \dfrac{1}{\sin y}}

\boxed{\cot y := \dfrac{\cos y}{\sin y}}

We know that

\csc y = \dfrac{-\sqrt{6} }{2}

Note that according to the definition of \csc y it is true that both sine and cosine are negative, once \csc y = \dfrac{-\sqrt{6} }{2} . Because \cot y > 0, this conclusion is true. We basically have

\boxed{(-a)(1/-b)=a/b \text{ such that } a,b\in\mathbb{R}_{\geq 0}}

Sure it is true \forall y\in\mathbb{R} but perhaps this way is better to understand.

In order to find sine, we can use the definition and manipulate the rational expression.

\csc y = \dfrac{-\sqrt{6} }{2} =  \dfrac{-\sqrt{6} / -\sqrt{6} }{2/-\sqrt{6} } = \dfrac{1 }{-\dfrac{2}{\sqrt{6} } }

Therefore,

\sin y =-\dfrac{2}{\sqrt{6} }

Here I just divided numerator and denominator by -\sqrt{6}.

Now, to find cosine we can use the identity

\boxed{\sin^2y +\cos ^2y =1}

Thus,

\left(-\dfrac{2}{\sqrt{6} }\right)^2 + \cos ^2y =1 \implies  \dfrac{4}{6 } +\cos ^2y =1

\implies  \cos ^2y =1 - \dfrac{4}{6 } \implies \cos ^2y  =\dfrac{1}{3 }   \implies  \cos y =    \pm \dfrac{\sqrt{1} }{\sqrt{3} } =  \pm \dfrac{\sqrt{1} \sqrt{3} }{3} = \pm  \dfrac{\sqrt{3}  }{3}

\cos y = \pm\dfrac{\sqrt{3}  }{3}

Once we have \cot y > 0, we just consider

\cos y = -\dfrac{\sqrt{3}  }{3}

FInally, for tangent, just consider

\boxed{\tan y := \dfrac{\sin y}{\cos y}}

thus,

\tan y = \dfrac{\sin y}{\cos y} = \dfrac{-\frac{2}{\sqrt{6} }}{-\frac{\sqrt{3}  }{3}} = \dfrac{6}{\sqrt{18} } =\dfrac{6}{3\sqrt{2} } =\dfrac{2}{\sqrt{2} } = \sqrt{2}

5 0
3 years ago
A horse had 4 1/5 scoops of oats in his bucket. He ate 2 1/2 scoops of oats. How many scoops of oats were left in his bucket ?
Sergeu [11.5K]

He has 1 7/10 scoops of oats left in his bucket.

5 0
3 years ago
Factor -1(x^(2)-3x-4) and pls show steps
soldi70 [24.7K]

Answer:(-x-1)(x-4)

Step-by-step explanation:

-1(x^{2} -3x-4)

factor the equation (multiples of 4 are 1 and 4 and 2 and 2) 4-1=1 so the factor you want to use are 1 and 4

-1(x +1)(x-4) --  -4+1=3

distribute the -1 into the first factor

(-x-1)(x-4)

8 0
3 years ago
Read 2 more answers
Cuál era la causa que lograba que el Imperio Romano mantuviera su unidad​
andrew11 [14]

Answer:

Causas de la decadencia del Imperio Romano

Otros factores que contribuyeron a la decadencia de Roma incluyen: -Inestabilidad política debida al tamaño del imperio. -Los intereses propios de las dos mitades del imperio. -La invasión de las tribus bárbaras.

Step-by-step explanation:

6 0
3 years ago
Solve for x. *<br> Round to nearest hundredths (0.00) and include unit labels.
Airida [17]
X=surd(19^2-11^2)
=15.5ft
7 0
3 years ago
Other questions:
  • Assume each variable has a different value. Which relations below are functions? a. {(a, b), (a, c), (a, d), (a, e)} b. {(a, b),
    14·2 answers
  • How to show work for 1634 divided by 19
    8·2 answers
  • What is 2/3+1/6= in a fraction plz
    11·1 answer
  • 3s+6≤-5(s+2)
    6·1 answer
  • Solve for x<br>I'm not sure of the way I answered it so can anyone help plz​
    15·1 answer
  • What is (2x9)- (15 divided by 3)
    5·2 answers
  • If a = 6 and b = 10, what does the following equal?<br> a² + b
    9·2 answers
  • If f(x) = (2x^3 − 4)^6, then what is f '(x)?
    8·1 answer
  • A. 39<br> B. 55<br> C. 66<br> D. 82
    5·1 answer
  • Divide: 37 / 0.05 please help
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!