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4 years ago

I need to "find the Indicated values" of each problem and I am very confused.

Mathematics

1 answer:

kotegsom [21]4 years ago

5 0

sorry i dunno i really dont i just need to finish my test lol

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Why is 3-48+30+15 = 0 please give detailed explanation

andrezito [222]

Answer:

Step-by-step explanation:

When dealing with an equation that only involves addition and subtraction ...you can solve it juat as it is witout using any special method same applied to equations tht involve only multiplication and division ... because they are an (inverse) of each other... hope it helps

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2 years ago

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Write an equation of the parabola with the vertex (-5,4) and focus (-5,0)

ch4aika [34]

Answer:

-0.4 or -10.4

Step-by-step explanation:

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3 years ago

Subtract the mixed numbers

Lisa [10]

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3 years ago

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The probability that a new advertising campaign will increase sales is assessed as being 0.80. The probability that the cost of

tatuchka [14]

Answer:

The probability that the cost is kept within budget or the campaign will increase sales is 0.88

Step-by-step explanation:

The probability that the cost is kept within budget (event A) or the campaign will increase sales (event B) is the union of the probability of those two events. By basic properties of probability, this is:

P(A ∪ B) = P(A) + P (B) - P(A ∩ B)

and for independent events:

P(A ∩ B) = P(A) * P(B)

So:

P(A ∪ B) = 0.80 + 0.40 - (0.80*0.40) = 1.20 - 0.32 = 0.88

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3 years ago

How do I do this? *Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

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3 years ago