3 years ago

Must the quadrilateral be a parallelogram?

Mathematics

1 answer:

Otrada [13]3 years ago

8 0

The answer is A. Yes, both pairs of opposite sides are parallel.

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Find the area of the parallelogram.

Dvinal [7]

Answer: 192

Step-by-step explanation: 24 • 8

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3 years ago

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For a cone, if the radius was quadrupled and the slant height was reduced to 1/6 of its original size what would be the formula

Paladinen [302]

Let $r$ be the radius of the cone's base and $\ell$ the slant height.

The surface area of a cone is

$A=\pi r^2+\pi r\ell$

If the radius is quadrupled ( $r\to4r$ ) and the slant height scaled by a factor of $\dfrac16$ , then the new area is

$A=\pi(4r)^2+\pi (4r)\left(\dfrac\ell6\right)$
$A=16\pi r^2+\dfrac23\pi r\ell$

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3 years ago

(2x-3)(x+5)<br> SHOW WORK FOR POINTS

vagabundo [1.1K]

(2x-3)(x+5)
Use foil to simplify, First multiply together the first terms of the pairs, then the outer terms, the middle terms, and finally the last terms. Then combine like terms.
2x^2+10x-3x-15 equals 2x^2+7x-15

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4 years ago

Important: Type only the number.

Nat2105 [25]

Answer:

Step-by-step explanation:

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3 years ago

Solve for y<br> <img src="https://tex.z-dn.net/?f=%20%5Csqrt2y-1-1%3D2" id="TexFormula1" title=" \sqrt2y-1-1=2" alt=" \sqrt2y-1-

Zolol [24]

I hope this helps you