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2 years ago

Which number, when rounded to the nearest tenth is 43.6?

Mathematics

1 answer:

andreev551 [17]2 years ago

7 0

Answer:

Step-by-step explanation:

43.55 rounds the tenth up because it has a hundredth of five

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Different ways to solve x+4=13

faltersainse [42]

One way is to move the 4 to other side so it would be x = 13 - 4 and that's x = 9

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3 years ago

The figure shown is made of two rectangular prisms.

AlladinOne [14]

I believe it’s expression c sorry if I’m incorrect

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3 years ago

Round 48.079 to the nearest tenth. A:48.08 B:48.8 C:50 D:48.1

tatiyna

Answer:

48.1

Step-by-step explanation:

Seven rounds up.

Hope this helped! :)

3 0

2 years ago

Read 2 more answers

Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted

Misha Larkins [42]

Answer:

$\frac{15}{28}$ is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red $= 3 + 5 = 8$

Probability of getting blue $= \frac{3}{8}$

Probability of not getting a blue $=\frac{5}{8}$

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

First Draw Blue, Second Draw Not Blue:

1st Draw: $P(Blue) = \frac{3}{8}$

2nd Draw: $P(Not\:Blue)=\frac{5}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}$

First Draw Not Blue, Second Draw Not Blue:

1st Draw: $P(Not\:Blue)=\frac{5}{8}$

2nd Draw: $P(Not\:Blue)=\frac{3}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}$

To get the probability of exactly one blue, we add both of the events:

$\frac{15}{56}+\frac{15}{56}=\frac{15}{28}$

4 0

3 years ago

You saved $20,000.00 and want to diversify your monies. You invest 45% in a Treasury bond for 3 years at 4.35% APR compounded an

Maru [420]

Compound Interest

A total of $20,000 is invested in different assets.

45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.

For this investment, the principal is P = 0.45*$20,000 = $9,000.

The compounding period is yearly, thus the interest rate is:

i = 4.35 / 100 = 0.0435

The duration (in periods) is n = 3

Calculate the final value with the formula:

$M=P_{}(1+i)^n$

Substituting:

$\begin{gathered} M=\$9,000_{}(1+0.0435)^3 \\ M=\$9,000\cdot1.136259062875 \\ M=\$10,226.33 \end{gathered}$

The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:

P = 15% of $20,000 = $3,000

i = 3.75 / 100 = 0.0375

n = 3

Calculating:

$\begin{gathered} M=\$3,000_{}(1+0.0375)^3 \\ M=\$3,000\cdot1.116771484375 \\ M=\$3,350.31 \end{gathered}$

The third investment is in a stock plan. The initial value of the investment is

P = 20% of $20,000 = $4,000

By the end of the first year, the stock plan increased by 8%, thus its value is:

M1 = $4000 * 1.2 = $4,800

By the end of the second year, the stock plan decreased by 4$, thus the value is:

M2 = $4,800 * 0.96 = $4,608

Finally, the stock plan increases by 6%, resulting in a final balance of:

M3 = $4,608 * 1.06 = $4,884.48

Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).

P = $20,000 - $9,000- $3,000 - $4,000 = $4,000

i = 2.90 / 100 = 0.029

n = 3

Calculating:

$\begin{gathered} M=\$4,000_{}(1+0.029)^3 \\ M=\$4,000\cdot1.089547389 \\ M=\$4,358.19 \end{gathered}$

To summarize, the final balances for each type of investment at the end of the third year are:

Investment 1; $10,226.33

Investment 2: $3,350.31

Investment 3: $4,884.48

Investment 4: $4,358.19

Total balance: $22,819.32

3 0

1 year ago