The shoes after a 7.5% tax is going to be 215 200/7.5 + 200 = C
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height
Answer:
The last graph.
Step-by-step explanation:
The first thing we look for is the y-intercept at -2. The only graphs where the line passes through the y-intercept at this point are the first and the last.
The slope of the line we want is -2/3. This means the line decreases; the first graph increases, not decreases, so it must be the fourth one..
Checking the fourth graph, from the y-intercept, we go down 2 and over 3 to find the next point; this means the slope is -2/3 and this is the correct line.
I'd say
Put one end of the compass on point P and the other end on point Q.
This way, you can construct (part of) a circumference with radius PQ with center P.
If you connect point P with any point on the circumference, this segment will be another radius of the circumference, and thus congruent to PQ.