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Rufina [12.5K]
3 years ago
5

What is the median of the following set of numbers?

Mathematics
1 answer:
katovenus [111]3 years ago
3 0

1 5

12 1 121

1

121

13

O A. 27

ОВ.

COIN

OC. .

12

OD. ????????????????

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The shoes cost $200 with a sales tax of<br> 7.5%, How much is the total Costs?
azamat
The shoes after a 7.5% tax is going to be 215 200/7.5 + 200 = C
4 0
3 years ago
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33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
Which graph represents a line with a slope of and a y-intercept equal to that of the line y = x – 2?
Rudiy27

Answer:

The last graph.

Step-by-step explanation:

The first thing we look for is the y-intercept at -2.  The only graphs where the line passes through the y-intercept at this point are the first and the last.

The slope of the line we want is -2/3.  This means the line decreases; the first graph increases, not decreases, so it must be the fourth one..

Checking the fourth graph, from the y-intercept, we go down 2 and over 3 to find the next point; this means the slope is -2/3 and this is the correct line.

3 0
3 years ago
Read 2 more answers
Can someone please help me with this question?!
RideAnS [48]
It is c the answer of it
6 0
3 years ago
18)
katovenus [111]

I'd say

Put one end of the compass on point P and the other end on point Q.

This way, you can construct (part of) a circumference with radius PQ with center P.

If you connect point P with any point on the circumference, this segment will be another radius of the circumference, and thus congruent to PQ.

7 0
3 years ago
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