Question

Please help!

Answer 1

Answer:

C. The second equation in system B is  $-7x=14$ .The solution to system B will be the same as the solution to system A.

Step-by-step explanation:

Given  

System A:

$5x-y=-11$

$3x-2y=-8$

System B:

$5x-y=-11$

When we multiply I equation of system A by -2 then we get new equation

$-10x+2y=22$ ( III equation )

Adding equation II  of system A and eqaution III then we get

$-7x=14$

Hence, II equation of system B

$-7x=14$

By division property of equality

$x=\frac{14}{-7}$

x=-2

Substitute the value of x=-2 in equation I of system B then we get

$5(-2)-y=-11$

-10-y=-11

By simplification

$-y=-11+10$=-1

y=1

By simplification

Therefore, the solution of system B is (-2,1).

Hence, option C is correct .

C. The second equation in system B is -7x=14 . The solution to system B will be the same as the solution to system A.

Answer 2

I think is b not sure