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Lena [83]
3 years ago
15

NEED ANSWER FAST !!

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

.-.

Explanation:

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You can separate visible light into parts called a
Step2247 [10]

Answer:

You can separate visible light into parts called a <em>Prism</em><em>.</em>

Explanation:

White light --- > VIBGYOR

<em>HOPE IT </em><em>HELPS</em><em>!</em>

7 0
3 years ago
Can yall help w this? iss times so try nd hurry :P
miss Akunina [59]

Answer:

The first option

Explanation:

No new compounds were added, and the pre existing ones wern't changed, so option one is the only one that makes sense.

Good luck!

4 0
3 years ago
Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
Paha777 [63]
Put a 3 on the Br2 and a 2 in front of the IBr3. You will then have 6Br on both sides, 2 I's on both sides.
8 0
3 years ago
When bsia is assembled as an octamer, what is most likely to be true regarding l76, l77, and l79?
telo118 [61]

The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

<h3>What is entropic penalty?</h3>

The entropic penalty in regards to ordered water is known to be one that tells or account  for any form of  weaker binding of the antibiotic novobiocin to what we call resistant mutant of DNA gyrase.

Note that in regards to the scenario above, the Entropic penalty is seen as the thermodynamically disfavored needs that is required in forming a cage of polar solvent molecules that is known to be seen around surface that has exposed hydrophobic potion of a molecule.

Hence, The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

Learn more about octamer from

brainly.com/question/13198179

#SPJ1

See full question below

When Bs1A is assembled as an octamer, what is most likely to be true regarding L76, L77, and L79?

A. They are oriented toward the solvent-exposed exterior of the protein assembly.

B. The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

C. Unlike in a monomer, they are not situated within the hydrophobic cap.

D. Their physiochemical properties are not substantially dependent on their hydrophobicity

5 0
3 years ago
Beryllium-11 is a radioactive isotope of the alkaline metal Beryllium. It decays at a rate of 4.9% every second. Assuming you st
rewona [7]

Answer:

11.02 % of an isotope will be left after 45 seconds.

Explanation:

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

N_o = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

t_{\frac{1}{2}} = half life of the isotope

\lambda = rate constant

We have :

Mass of Beryllium-11 radioactive isotope= N_o=100

Mass of Beryllium-11 radioactive isotope after 45 seconds = N=?

t = 45 s

\lambda = rate constant  = 4.9 \% s^{-1}=0.049 s^{-1}

N=N_o\times e^{-(\lambda \times t}

Now put all the given values in this formula, we get

N=100\times e^{-0.049 s^{-1}\ties 45 s}

N=11.02 g

Percentage of isotope left :

\frac{N}{N_o}\times 100=\frac{11.02 g}{100 g}\times 100=11.02\%

11.02 % of an isotope will be left after 45 seconds.

7 0
4 years ago
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