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otez555 [7]
3 years ago
5

Classify each reaction as endothermic or exothermic.

Chemistry
2 answers:
evablogger [386]3 years ago
7 0

H2 + Br2 → 2HBr, ΔH = -73 kJ    Exothermic

2NH3 → N2 + 3H2, ΔH = 92 kJ     Endothermic

CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ     Exothermic

2HCl → H2 + Cl2, ΔH = 184 kJ         Endothermic

Alik [6]3 years ago
5 0

The correct answers are

Exothermic:

H2 + Br2 → 2HBr, ΔH = -73 kJ    

CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ

Endothermic

2NH3 → N2 + 3H2, ΔH = 92 kJ    

2HCl → H2 + Cl2, ΔH = 184 kJ    

:)  

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I just started learning about kinetic molecular theory, and I’m not sure how to answer the question circled below
lions [1.4K]

Answer : The value of 'R' is 0.0821\text{ L atm }mol^{-1}K^{-1}

Solution : Given,

At STP conditions,

Pressure = 1 atm

Temperature = 273 K

Number of moles = 1 mole

Volume = 22.4 L

Formula used :     R=\frac{PV}{nT}

where,

R = Gas constant

P = pressure of gas

T = temperature of gas

V = volume of gas

n = number of moles of gas

Now put all the given values in this formula, we get the values of 'R'.

R=\frac{(1atm)\times (22.4L)}{(1mole)\times (273K)}

R=0.0821\text{ L atm }mol^{-1}K^{-1}

Therefore, the value of 'R' is 0.0821\text{ L atm }mol^{-1}K^{-1}.

7 0
3 years ago
Which statement is true regarding the diagram of circle P? The sum of y and z must be 2x. The sum of y and z must be x. The diff
olga2289 [7]

Answer:

The difference of Z and Y must be 2x

Explanation:

6 0
3 years ago
Read 2 more answers
qual a concentração de uma solução contendo 50g de cloreto de sódio dissolvidos em 250ml de solução​
anygoal [31]

Answer:

200 g/L

Explanation:

The concentration of a solution (also called molarity) can be calculated with the formula:

M=\frac{m}{V}

where

m is the mass of the solute

V is the volume of the solution

For the solution in this problem we have:

m = 50g is the mass of the solute

V = 250 mL = 0.250 L is the volume of the solution

Therefore, the concentration of the solution is:

M=\frac{50 g}{0.250 L}=200 g/L

6 0
3 years ago
The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.751 g sample of e
fredd [130]

<u>Answer:</u> The empirical formula for the given compound is C_{4}H_{10}O

<u>Explanation:</u>

The chemical equation for the combustion of ether follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=4.159g

Mass of H_2O=2.128g

Mass of sample = 1.751 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 4.159 g of carbon dioxide, \frac{12}{44}\times 4.159=1.134g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.128 g of water, \frac{2}{18}\times 2.128=0.236g of hydrogen will be contained.

Mass of oxygen in the compound = (1.751) - (1.134 + 0.236) = 0.381 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.134g}{12g/mole}=0.0945moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.236g}{1g/mole}=0.236moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.381g}{16g/mole}=0.0238moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0238 moles.

For Carbon = \frac{0.0945}{0.0238}=3.97\approx 4

For Hydrogen = \frac{0.236}{0.0238}=9.91\approx 10

For Oxygen = \frac{0.0238}{0.0238}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 10 : 1

Hence, the empirical formula for the given compound is C_{4}H_{10}O

7 0
3 years ago
Jason is preparing curry from an Indian cookbook his British brother-in-law gee him for his birthday. Unfortunately, the British
Marina CMI [18]

Answer:

0.99 pounds

2,000 oz

0.423 cups

Explanation:

In order  to convert this units we need to look up their equivalences.

1 g equals 0,0022 pounds approximately

Then we need to cross-multiply:

\frac{1 g}{0.0022 pounds} = \frac{450 g}{ Xpounds} \\x = \frac{450 g x 0.0022 pounds}{1 g}

450 g equals 0.99 pounds approximately

We can do the same calculation for the other 2 ingredients

1 g equals 16 oz

Then (125 g x 16 oz) / 1 oz = 2,000 oz  (or 500 4 oz)

1 cup equals 236.59 ml

Then (100 ml x 1 cup)/ 236.59 = 0.423 cups

6 0
3 years ago
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