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otez555 [7]
3 years ago
5

Classify each reaction as endothermic or exothermic.

Chemistry
2 answers:
evablogger [386]3 years ago
7 0

H2 + Br2 → 2HBr, ΔH = -73 kJ    Exothermic

2NH3 → N2 + 3H2, ΔH = 92 kJ     Endothermic

CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ     Exothermic

2HCl → H2 + Cl2, ΔH = 184 kJ         Endothermic

Alik [6]3 years ago
5 0

The correct answers are

Exothermic:

H2 + Br2 → 2HBr, ΔH = -73 kJ    

CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ

Endothermic

2NH3 → N2 + 3H2, ΔH = 92 kJ    

2HCl → H2 + Cl2, ΔH = 184 kJ    

:)  

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Answer:

<h2>It'll float</h2><h2>Less than 1g/cm3 it'll float in water </h2>

4 0
3 years ago
How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O? The reaction is:
Readme [11.4K]

Answer:

There is 5.72 grams of H2 formed

1)  C+ H2O → CO + H2

2) We start with 34 grams of carbon that will react with an excess of H2O

3) 5.72 grams of H2

Explanation:

Step 1: Data given

Mass of carbon = 34.00 grams

H2O is in excess

Molar mass of C = 12 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

C+ H2O → CO + H2

Step 3: What is the starting substance

We start with 34 grams of carbon that will react with an excess of H2O

Step 4: Calculate moles carbon

Moles C = mass C / molar mass C

Moles C = 34.00 grams / 12.00 g/mol

Moles C = 2.833 moles

Step 5: Calculate moles H2

Carbon is the limiting reactant.

For 1 mol Carbon we need 1 mol H20 to produce 1 mol CO and 1 mol H2

For 2.833 moles C we'll have 2.833 moles H2

Step 6: Calculate mass of H2

Mass H2 = moles H2 * molar mass H2

Mass H2 = 2.833 moles * 2.02 g/mol

Mass H2 = 5.72 grams of H2

8 0
4 years ago
Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl
Ugo [173]

0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.

Explanation:

Data given:

Volume of the base = 47 ml

molarity of the base= 0.39 M

volume of the acid = 25 ml

molarity of the acid =?

For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined.  The formula used:

Macid X Vacid = Vbase x Mbase

Macid = \frac{Vbase X M base}{V acid}

putting the values given in the rearranged equation above:

Macid = \frac{0.39 x47}{25}

           = 0.73 M

The concentration of the sulphuric acid needed is 0.73 M.

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Answer:

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Explanation:

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