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puteri [66]
3 years ago
13

1 divided by 0.80. Please show work.

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0

It would be 1.25

1/.8 = 10/8 = 8 goes into 10 once and there is 2/8 left over so the answer is..

1 2/8 or simplified 1 1/4 or 1.25

lozanna [386]3 years ago
4 0

divide 1 by 0.8=1.25

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kow [346]

The value of h(t) when t=\frac{15}{32} is 10.02.

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Given function h(t)=-16t^2+15t+6.5

To find the value of h(t) when t=\frac{15}{32}:

h(t)=-16t^2+15t+6.5

Substitute t=\frac{15}{32} in the given function.

$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5

            $=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5

Now multiply the common terms into inside the bracket.

           $=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5

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          $=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

        $=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}

        $=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}

        $=\frac{-225+450+416}{64}

       $=\frac{641}{64}

       = 10.02

$h\left(\frac{15}{32} \right)=10.02

Hence the value of h(t) when t=\frac{15}{32} is 10.02.

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If h(x)= -4x-10, find h(-5).
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h= −4x−10/x

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