Answer with explanation:
Class Interval Variate Frequency
16-18 16 1
19-21 0 0
22-24 0 0
25-27 26,27 2
Answer:
352x^2
Step-by-step explanation:
40\times 1.25x\times 2.20x\times 3.2040×1.25x×2.20x×3.20
(40)1.25x2.20x3.20
+ − . ln > <
× ÷ / log ≥ ≤
( ) logx = %
1 Take out the constants.
(40\times 1.25\times 2.20\times 3.20)xx(40×1.25×2.20×3.20)xx
2 Simplify 40\times 1.2540×1.25 to 5050.
(50\times 2.20\times 3.20)xx(50×2.20×3.20)xx
3 Simplify 50\times 2.2050×2.20 to 110110.
(110\times 3.20)xx(110×3.20)xx
4 Simplify 110\times 3.20110×3.20 to 352352.
352xx352xx
5 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
352{x}^{2}352x
2
Done
Answer:
Statement 3
Step-by-step explanation:
y = -2/3x-24
Make x the subject
y + 24 = -(⅔)x
x = -(3/2)(y + 24)
Intersection variables
f^-1(x) = -(3/2)(x + 24)
Slope: -3/2
No domain restrictions
y-intercept: x = 0
-(3/2)(0+24)
-36
(0,-36)
x-intercepts: y = 0
0 = -(3/2)(x + 24)
x = -24
(-24,0)
Linear function, range is all real values of y
50-(30.8+4.9)=14.3 kg.
You start with 50 then you need to subtract 30.8 and 4.9 from it. So you add them together and get 35.7. Then you subract 25.9 from 50 and get 14.3 kg.
Step-by-step explanation:
here ! I used the formula area = length × width
and just some algrbric expressions solving
