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3 years ago

Which of the following functions has the greatest y-intercept?

2 answers:

7 0

The y intercept occurs when x = 0 so in the case of the first function it is y = 3

g(x) = 3 cos 2x + 1

when x = 0 g(x) = 3 cos 0 + 1 = 3*1 + 1 = 4

so the answer is g(x)

wolverine [178]3 years ago

5 0

Answer:

g(x) has greatest y-intercept.

Step-by-step explanation:

We are given a table of values for function f(x) as:

x y=f(x)

−3 −14

−2 −6

−1 −2

1 5

2 6

We know that the y-intercept of a function is a point where the x-value is zero.

i.e. the input value is zero.

Hence, after looking at the table of values of the function f(x) we have the y-intercept of the function f(x) is:

y=3

Also we are given function g(x) as:

g(x) = 3 cos(2x) + 1

Hence, we calculate the y-intercept of the function g(x) by taking x=0

on taking x=0 we have:

g(0)=3 cos(0)+1

g(0)=3+1=4

Hence, the y-intercept of function g(x) is 4.

Hence, g(x) has the greatest y-intercept.

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The area of a triangle is found using the following formula:

attashe74 [19]

Answer:

12 in.2

Step-by-step explanation:

The formula for a triangle is b*h/2

3*8 = 24

24/2 = 12

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3 years ago

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Ingrid spends $120 on car repairs. Which integer represents the amount of money Ingrid must earn in order to create a zero pair?

Julli [10]

Answer: -120

Step-by-step explanation:

this would be the answer because if you take a positive and add it to a negative you get zero if their the additive inverse of the number.

8 0

2 years ago

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A standard number cube is tossed. Find the following probability. P(greater than 4 or odd)

lorasvet [3.4K]

A standard cube has 6 possible outcomes. But since we want to find P(4+ or odd), the outcomes become more narrow.
So:
6 outcomes -> 1, 2, 3, 4, 5, 6

But we want to find 4+
So:
4+ = 4, 5, 6

We also want to find all odd possibilities.
So:
odd = 1, 3, 5

As you can see, there is a 5 in both the 4+ and the odd numbers so 5 will only be counted once.
P(4+ or odd) = 1, 3, 4, 5, 6

So the probability of having an outcome that is P(4+ or odd) is:
5/6 or 0.8333 or 83.33%

Hope I helped!

8 0

3 years ago

Read 2 more answers

Greg and Heather each opened a savings account today. Greg opened his account with a starting amount of $330, and he is going to

cluponka [151]

Set up two equations:

Greg = 330 + 75X

Heather = 660 + 45x

Set them to equal and solve for x:

330 + 75x = 660 + 45x

Subtract 330 from both sides:

75x = 330 + 45x

Subtract 45x from both sides:

30x = 330

Divide both sides by 30:

x = 330 / 30

X = 11

11 months they will have the same amount saved.

6 0

3 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago