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Ivenika [448]
3 years ago
12

Rob cuts 15-foot wire into 8 equal pieces. About how long is each piece

Mathematics
2 answers:
djverab [1.8K]3 years ago
6 0
<span>1.875 feet each. 1.875* 6= 15

</span>
sdas [7]3 years ago
6 0

<u>Answer</u>

1.857


<u>Explanation</u>

The wire is 15 foot. Rop is to get 8 pieces.

If you are to get the length of each piece, we divide 15 by 8.

15 ÷ 8 = 15/8

          = 1.875 foot

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You buy a lottery ticket to a lottery that costs $10 per ticket. There are only 100 tickets available to be sold in this lottery
riadik2000 [5.3K]

Answer:

Loss of $1.20

Step-by-step explanation:

The possible outcomes for this lottery and their probabilities are:

- a 1 in 100 chance of winning $450

- a 2 in 100 chance of winning $120

- a 4 in 100 chance of winning $30

- a 93 in 100 chance of losing $10

Therefore, the expected value of this lottery when buying one ticket is:

E(X) = \frac{1}{100}*\$450+ \frac{2}{100}*\$120+ \frac{4}{100}*\$30-\frac{93}{100}*\$10 \\E(X) = -\$1.2

Therefore, you are expected to lose $1.2 per ticket.

3 0
3 years ago
unit 1 chapter 1 gross income answersA portion of Donald Irwin’s time sheet is shown below. Determine the total number of hours
statuscvo [17]

Answer:

i need points

Step-by-step explanation:

7 0
3 years ago
3. From the table below, find Prof. Xin expected value of lateness. (5 points) Lateness P(Lateness) On Time 4/5 1 Hour Late 1/10
wariber [46]

Answer:

The expected value of lateness \frac{7}{20} hours.

Step-by-step explanation:

The probability distribution of lateness is as follows:

  Lateness             P (Lateness)

  On Time                     4/5

1 Hour Late                  1/10

2 Hours Late                1/20

3 Hours Late                1/20​

The formula of expected value of a random variable is:

E(X)=\sum x\cdot P(X=x)

Compute the expected value of lateness as follows:

E(X)=\sum x\cdot P(X=x)

         =(0\times \frac{4}{5})+(1\times \frac{1}{10})+(2\times \frac{1}{20})+(3\times \frac{1}{20})\\\\=0+\frac{1}{10}+\frac{1}{10}+\frac{3}{20}\\\\=\frac{2+2+3}{20}\\\\=\frac{7}{20}

Thus, the expected value of lateness \frac{7}{20} hours.

8 0
3 years ago
3. A principal orders 2,592 pencils. She gives an equal amount to each of
AfilCa [17]
Each teacher should receive 108 pencils
3 0
3 years ago
Your English teacher has decided to randomly assign poems for the class to read. The syllabus includes four poems by Shakespeare
Tresset [83]
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.

So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.

At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39

The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
6 0
4 years ago
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