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3 years ago

What is the answer to this question?

Mathematics

1 answer:

amid [387]3 years ago

5 0

Answer:

Step-by-step explanation:

Hello!

2*2* 5+ 2*2*4 =

20 + 16 = 36 cm³

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Marissa borrowed $5,500 from the bank and paid $1,100 in interest. To identify the interest rate, she needed to find what percen

blagie [28]

Answer:

0.2 which is 20%

Step-by-step explanation:

divide $5,500 from $1,100. Which equals 0.2 or 20%.

I hope this helped if not im am so sorry

4 0

3 years ago

Please solve<br>x^2+x-6006=0

Ratling [72]

Step-by-step explanation:

x^2+x-6006=0

x^2+78x-77x-6006=0

x(x+78)-77(x+78)=0

(x-77)(x+78)=0

=>x=77 or x=78

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3 years ago

Solve the following Equations<br> A)x-1=5 <br> B)2m-1=9

Allisa [31]

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3 years ago

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Adding fractions 1/6+2/3=

mars1129 [50]

Answer:

$\frac{5}{6}$

$\frac{1}{6} + \frac{2}{3}$ is equivalent to $\frac{1}{6} + \frac{4}{6}$ .

This is because $\frac{2}{3}=\frac{4}{6}$

The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

$\frac{1}{6} + \frac{4}{6} =\frac{5}{6}$

This is because 4 + 1 = 5.

Your answer is $\frac{5}{6}$ .

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

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3 years ago

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In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in

tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.35$ estimated proportion (value assumed)

$p$ true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: