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nirvana33 [79]
2 years ago
5

Which of the following is the radical expression of 2d^7/10

Mathematics
1 answer:
elena-s [515]2 years ago
3 0

Answer:

\sqrt[10]{2d^{7} }

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Name the quantity measured by each of the seven si base units and give the si symbol of the unit
Nikolay [14]

Answer:

Length , time, mass, current, temperature, amount of mass, luminous intesity

m, sec, kg, A, K, mol, cd

Step-by-step explanation:

Seven basic SI units are used for measurement of

Meter for length

Second for time

Kilogram for mass

Ampere for current

Kelvin for temperature

Mole for amount of mass

Candela for luminous intensity

Symbols of these SI units are

m for meter

sec for second

kg for kilogram

A for ampere

K for kelvin

mol for mole

cd for candela

5 0
3 years ago
Do not pass go. proposition or not?
kolbaska11 [484]
I believe it is proposition
8 0
3 years ago
Vallues of 3×-2ײ=7​
mrs_skeptik [129]

Answer:

Step-by-step explanation:

"Find the values of x that satisfy 3x - 2x^2 = 7."  Please do not use " × " to represent a variable; " × " is an operator, the "multiply" operator.

Rearrange these three terms in descending order by powers of x:

-2x^2 + 3x - 7 = 0.   Here the coefficients are a = -2, b = 3 and c = -7, and so the discriminant of this quadratic is b^2-4ac, or 9 - 4(-2)(-7), or 9 - 56, or -47.

Because the discriminant is negative, we'll have two different complex roots here.  The quadratic formula becomes

       -3 ± i√47         -3 ± i√47

x = ----------------- = -------------------

        2(-2)                     -4

6 0
3 years ago
Https://imgur.com/a/p0QjLGl
inna [77]

Answer: what’s the link about ?

3 0
3 years ago
Read 2 more answers
Probabilities. Please help
Anon25 [30]

In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.

P=(no. of favourable outcomes)/(no. of possible outcomes)

When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.

1) P(getting 1)=1/6

expected frequency of getting 1

=P(getting)1)×no. of trials

=1/6×600=100

But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.

Therefore, the dice is not fair.

2) P(getting a tail)=0.3

estimate for the number of times the coin will land on a tail

=expected frequency of getting a tail

=P(getting a tail)×no. of trials

=0.3×150=45

3)P(getting a six)=2/3

expected frequency of getting a six

=P(getting a six)×no. of trials

=2/3×300=200

4)P(getting a three)=0.5

expected frequency of getting a three

=P(getting a three)×350

=0.5×350=175

3 0
3 years ago
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