Answer:
a, f, c e
Step-by-step explanation:
1/10 = 10/100
So we need to find 10% of 300.
0.10 x 300 = 30
Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
Answer:
y = x^2 + 9x + 6 No remainder.
Step-by-step explanation:
The divisor will be 3 The sign on the divisor switches.
3 || 1 + 6 - 21 - 18 ||
3 27 + 18
================================
1 9 6 0
The answser is x^2 + 9x + 6
