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Rina8888 [55]
3 years ago
11

How many square feet of outdoor carpet will we need for this hole

Mathematics
2 answers:
Mila [183]3 years ago
6 0

Answer:

36\text{ inch}^2

Step-by-step explanation:

We have been given an image of outdoor carpet needed for a hole. We are asked to find the area of outdoor carpet needed for this hole.

We can see that there are two pieces needed to cover the given hole.

One pieces equal 24 square inches and another pieces equal 12 square inches.

\text{Area of carpet needed to cover the hole}=24\text{ inch}^2+12\text{ inch}^2

\text{Area of carpet needed to cover the hole}=36\text{ inch}^2

Therefore, 36\text{ inch}^2 of carpet is needed to cover the given hole.

olasank [31]3 years ago
3 0

Answer: 36 sq


Step-by-step explanation: you add 24 to 12 and get 36



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Natali5045456 [20]
78/6=13    theres not much to it just divide
                                 


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3 years ago
What is the sum of 1/8 + 5/16 + 3/8<br><br> 9/32<br> 13/32<br> 9/16<br> 13/16
den301095 [7]

11/16 sorry I’m stxxupid

6 0
3 years ago
Read 2 more answers
3t-8 I’m not sure pls help me
densk [106]

Answer: 3t-8

Step-by-step explanation:

<em>3t-8 is the answer because there are no like terms.</em>

<em />

6 0
3 years ago
The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =
gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

f_x(x)  = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0

Thus, the expected  total claim amount \mu =  1000

The variance of the total claim amount \sigma ^2  = 1000^2

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})

P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})

P(X>1100n) = P(Z> \dfrac{10*100}{1000})

P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345

\mathbf{P(X>1100n) = 0.158655}

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

4 0
2 years ago
How do you solve -36x+2/4 (the “/“ is because it’s a fraction)
butalik [34]

you cannot solve this because it is an expression.  you need an equals to make it an equation.

-36x + 2/4 is an expression which can be simplified

-36x+1/2

6 0
3 years ago
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