A LR parser is called a shift-reduce algorithm, because in most cases it either shifts the next lexeme of input onto the parse stack or reduces the handle that is on top of the stack.
<u>Explanation:</u>
A parser is that aspect of the compiler which practices a token string as input and with the sustenance of enduring grammar, transforms it into the identical parse tree. The LR parser is a non-recursive, shift-reduce, bottom-up parser. It utilizes a broad range of context-free grammar which gives it the most valuable syntax analysis procedure.
LR means that the data is examined left-to-right and that a rightmost source, in reverse, is assembled. LR parsers relish time and space extended in the size of the input. Practically all programming languages possess LR grammars.
Answer: (a), (b), (c), and (d)
Step-by-step explanation:
Check the options
![(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x](https://tex.z-dn.net/?f=%28a%29%5C%5C%5CRightarrow%20%5B%5Csin%20x%2B%5Ccos%20x%5D%5E2%3D%5Csin%20%5E2x%2B%5Ccos%20%5E2x%2B2%5Csin%20x%5Ccos%20x%5C%5C%5CRightarrow%20%5B%5Csin%20x%2B%5Ccos%20x%5D%5E2%3D1%2B2%5Csin%20x%5Ccos%20x%5C%5C%5CRightarrow%20%5CRightarrow%20%5B%5Csin%20x%2B%5Ccos%20x%5D%5E2%3D1%2B%5Csin%202x)
![(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x](https://tex.z-dn.net/?f=%28c%29%5C%5C%5CRightarrow%20%5Cdfrac%7B%5Csin%203x%7D%7B%5Csin%20x%5Ccos%20x%7D%3D%5Cdfrac%7B3%5Csin%20x-4%5Csin%20%5E3x%7D%7B%5Csin%20x%5Ccos%20x%7D%5C%5C%5C%5C%5CRightarrow%203%5Csec%20x-4%5Csin%20%5E2x%5Csec%20x%5C%5C%5CRightarrow%203%5Csec%20x-4%5B1-%5Ccos%20%5E2x%5D%5Csec%20x%5C%5C%5CRightarrow%20%203%5Csec%20x-4%5Csec%20x%2B4%5Ccos%20x%5C%5C%5CRightarrow%204%5Ccos%20x-%5Csec%20x)
![(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x](https://tex.z-dn.net/?f=%28d%29%5C%5C%5CRightarrow%20%5Cdfrac%7B%5Csin%203x-%5Csin%20x%7D%7B%5Ccos%203x%2B%5Ccos%20x%7D%3D%5Cdfrac%7B2%5Ccos%20%5B%5Cfrac%7B3x%2Bx%7D%7B2%7D%5D%20%5Csin%20%5B%5Cfrac%7B3x-x%7D%7B2%7D%5D%7D%7B2%5Ccos%20%5B%5Cfrac%7B3x%2Bx%7D%7B2%7D%5D%5Ccos%20%5B%5Cfrac%7B3x-x%7D%7B2%7D%5D%7D%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7B2%5Ccos%202x%5Csin%20x%7D%7B2%5Ccos%202x%5Ccos%20x%7D%3D%5Cdfrac%7B%5Csin%20x%7D%7B%5Ccos%20x%7D%5C%5C%5C%5C%5CRightarrow%20%5Ctan%20x)
Thus, all the identities are correct.
Answer:
She needs to sell the rest of her <u>29.41 </u>rolls of wrapping paper. If she sells all of her rolls of wrapping paper, she'll be able to get a total of <u>$131.48.</u>
Step-by-step explanation:
To get the answer to "<u>How many more rolls of wrapping paper does Daisy need to sell?"</u> you would have to add up how many she already sold which is
2.24 + 5.75 + 0.6 = 8.59
and then subtract 8.59 from the total of rolls she's supposed to sell.
38 - 8.59 = 29.41
To get <u>$131.48</u>
You multiply how much each roll costs to the total of rolls she's supposed to sell:
38 * 3.46 = <u>131.48</u>
Hope this helped :)
Answer:
This means we reject that all the three groups have same means.
Step-by-step explanation:
given that in a one-way ANOVA, we reject the statement in the null hypothesis if three treatment groups are being compared
In anova one way we compare the means of more than two groups.
The hypotheses are set up as
H0: Means of all three groups are equal against
Ha: atleast two means are different
When we find out F statistic by dividing SST by MST
we get p value.
Whenever p is less than significant level, we reject null hypothesis
This means we reject that all the three groups have same means.
Then we can go further to check up which pair is different by doing Tukey test or pairwise t test.
Answer:
sry i cant help you bcoz i havent read this type of exercise yet
