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Ierofanga [76]
3 years ago
13

Which of the following are identities? check all that apply.

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x

(b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)

(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow  3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x

(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x

Thus, all the identities are correct.

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The quadrilateral shown is rotated 90° clockwise about the origin. In which quadrant is the image of the quadrilateral located?
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Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

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Raphael wants to join a game-of-the-month club. The first club costs $60 to
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Ju Chan solved the previous question by finding the expression 4(-15). Which addition problem would give the same result? Choose
Umnica [9.8K]

Answer:

C. (-1)(15+15+15+15)

D. (-15)+(-15)+(-15)+(-15)

Step-by-step explanation:

The original expression: 4(-15)=-60

Let's try choice A: 15+15+15+15=60(not a negative number, so does not work)

Let's try choice B: 4+4+4+4=16(nowhere near -60)no

Let's try choice C: (-1)(15+15+15+15)=(-1)(60)=-60--yes

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Only choices C and D work.

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3 years ago
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Answer:

\angle CBF

\angle GBE

Step-by-step explanation:

\angle CBF is supplementary to \angle CBE

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\angle GBE is also supplementary to \angle CBE

m\angle GBF +  \angle CBE = 180\degree

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