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Ierofanga [76]
3 years ago
13

Which of the following are identities? check all that apply.

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x

(b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)

(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow  3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x

(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x

Thus, all the identities are correct.

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I dont know how to do graphing pls help
yarga [219]

Answer:

Solution: (-1, -1)

Step-by-step explanation:

y=4x+2

y=-4/3x-2

Solve by graphing.

First, you need to plot the y-intercept.

y=4x+<u>2</u>

2 will be your y-intercept.

Next, you plot your slope.

y=<u>4x</u>+2

From your y-intercept, you will go up 4 and right one space, if you run out of space go down 4 and left 1.

Now repeat the same steps for the next one.

y=-4/3x<u>-2</u>

Plot your y-intercept.

y=<u>-4/3x</u>-2

because your slope is negative you will go down 4 and right 3, if you run out of room go up 4 and left 3.

Then draw connecting lines and wherever the lines intersect, that's going to be your solution. In this case, the solution is (-1, -1).

Hope this helps :)

4 0
3 years ago
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ANSWER QUESTION PLEASE!!
Fynjy0 [20]

Answer:

W = 2t + 8

Step-by-step explanation:

weight from birth plus number of months times 2 equals your total weight.

5 0
3 years ago
Answers need help!!!!!!
Gala2k [10]
<h3>Step-by-step explanation:</h3>

<u>Pythagorus theorum:</u>

9² = 3² + YZ²

81 - 9 = YZ²

√72 = YZ

∴YZ= 8.48 ≈ 8.5

<u>Trigonometry:</u>

We have adjacent as 3, and hypotenuse as 9

cos X = 3/9

X= cos∧-1 (3/9) → <em>[cos inversed]</em>

∴X= 70.5°

We have opposite as 3 and hypotenuse as 9

sin Z= 3/9

Z= sin∧-1 (3/9)→<em> [sin inversed]</em>

∴Z= 19.47 ≈ 19.5

4 0
3 years ago
Can someone please help me with these questions!! Thanks,
fiasKO [112]

6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1

6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)

6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)

6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²

8 0
3 years ago
2
Mademuasel [1]

Answer:

I only                                                                

Step-by-step explanaition:

The domain (x) can not repeat in order for it to be a function.

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