An angle bisector of a triangle divides the opposite side of the triangle into segments2 cm and 5cm long. The second side of the
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Given:
One midsegment of an equilateral triangle.
To find:
The ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths.
Solution:
All sides of an equilateral triangle are same.
Let a be the each side of the equilateral triangle.
Length of the midsegment is equal to the half of the non included side or third side.
The sum of two side is
Now, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is
Therefore, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is 1:4.
<h3>Given : </h3>
- Base of triangle = 8 cm
- Height of triangle = 4 cm
- Area of triangle = ?
As, we have :
- Base of triangle, b = 8 cm
- Height of triangle, h = 4 cm
So, to find area of triangle we have a formula :
Hence, area of given triangle is 16 cm².