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ziro4ka [17]
3 years ago
12

Write a C class, Flower, that has three member variables of type string, int, and float, which respectively represent the name o

f the flower, its number of pedals, and price. Your class must include a constructor method that initializes each variable to an appropriate value, and your class should include functions for setting the value of each type, and getting the value of each type.
Computers and Technology
1 answer:
Ulleksa [173]3 years ago
3 0

Answer and Explanation:

C is a low level language and does not have classes. The language isn't based on object oriented programming(OOP) but is actually a foundation for higher level languages that adopt OOP like c++. Using c++ programming language we can implement the class, flower, with its three variables/properties and functions/methods since it is an object oriented programming language.

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Create two classes. The first, named Sale, holds data for a sales transaction. Its private data members include the day of the m
olya-2409 [2.1K]

Answer:

A C++ program was used in creating two classes. the code is stated below.

Explanation:

Solution

The C++ program is executed below:

#include<iostream>

using namespace std;

//declare class (will be define later)

class Salesperson;

//class Sale

class Sale

{

  //private members of class

  private:

      string day;

      double amtOfSale;

      int salesPersonId;

 //public methods

  public:

      //constructor that takes day,amount of sale and salesPersonId as parameters

      Sale(string date,double sale,int id)

      {

          //set the private members to the initial values passed

          day=date;

          amtOfSale=sale;

          salesPersonId=id;

      }    

      //declare a friend function that takes objects of the two classes as parameters

      friend void display(Sale,Salesperson);

};  

//define class Salesperson

class Salesperson

{

  //private members of the class

  private:

      int salesPersonId;

      string lastName;    

  //public methods

  public:

      //constructor that takes name and id as parameters

      Salesperson(int id,string name)

      {

          //set the members of the class with the parameters passed

          salesPersonId=id;

          lastName=name;

      }  

      //declare a friend function that takes objects of the two classes as parameters

      friend void display(Sale,Salesperson);

};

//define the friend funtion

void display(Sale saleObj,Salesperson personObj)

{

  //display the sales info using the objects of the two classes

  cout<<"\nSale #"<<saleObj.salesPersonId<<" on "<<saleObj.day<<" for $"<<saleObj.amtOfSale<<" sold by #"<<personObj.salesPersonId<<" "<<personObj.lastName;

}  

int main()

{

  //create object for Sale class and pass default values

  Sale sObj1("12/25/2016",559.95,103);

  //create object for Salesperson class and pass default values

  Salesperson pObj1(103,"Woods");

 

  //create another object for Sale class and pass default values

  Sale sObj2("11/15/2016",359.95,106);

  //create another object for Salesperson class and pass default values

  Salesperson pObj2(106,"Hansen");

  //using the friend function dislay the sales info

  display(sObj1,pObj1);

  display(sObj2,pObj2);

  return 0;

}

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What is the recommended solution to configure this automated behavior? UC has a requirement that an opportunity should have a fi
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The answer will need to be workflow.
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To display the size of your backup file, you can use the Windows program called: Windows Explorer Scan disk Defrag Windows Acces
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Windows Explorer scan disk
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Machine code and Object code is the same right?​
guapka [62]

Answer:

"True" Machine code and Object code is the same.

Explanation:

All code at the same level is considered the same code, so we can say that the machine code, byte code, and the object code with it is of the same type, all of which are considered as the lowest level associated with the common program, these are common. Also known as source code because it is used in translating different languages.

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You just finished training a decision tree for spam classification, and it is gettingabnormally bad performance on both your tra
strojnjashka [21]

Answer:

Option B is the correct option.

Explanation:

The following answer is true because when the person completed our training of a decision tree and after the following presentation he getting not good working performance on both side i.e., test sets and during the training period. After the training there is no bug on the implementation of the presentation then, he has to increase the rate of the learning.

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