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timama [110]
2 years ago
10

A computer’s memory is composed of 8K words of 32 bits each. How many bits are required for memory addressing if the smallest ad

dressable memory unit is a word?
13

8

10

6

32
Computers and Technology
1 answer:
victus00 [196]2 years ago
7 0

Answer:

The minimum number of bits necessary to address 8K words is 13.

Explanation:

You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.  

8000 words can be addressed with 2^{n}  units. Now you have to find the value of n that approximates to the number of words.  

2^2=4\\2^4=16\\2^7=128\\2^{10}=1024\\2^{12}=4096\\2^{13}=8192

So you can see that 13 bits are needed to address 8K words.

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Answer:

 The solution code is written in Python 3:

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  3. if(calories > 0 and fats > 0):
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Explanation:

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Then we proceed to next input validation to check if calories from fact more than total calories. If so, proceed to calculate percentage of calories from fats and if it is lower than 30%, display the appropriate message (Line 6 - 9). If fail the second input validation, the program will display another error input message again (Line 11)

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