Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is




Slope of lines NY is




Product of slopes of two perpendicular lines is -1. So,


The perpendicular bisector of NY passes through (-4,1) with slope
. So, the equation of perpendicular bisector of NY is




Add 1 on both sides.

Therefore, the equation of perpendicular bisector of NY is
.
Answer:
176
Step-by-step explanation:
just simplify the given mathematical statement
Answer:
h = 1,268 cm
Step-by-step explanation:
V = (π·r²·h)/3, general formula
83 = (π·4²·h)/3, substitute what is given V= 83 cm³ and r = 4 cm
83 ·3 = (π· 16·h)·3/3, multiply both sides by 3 and solve 4² = 16
249 = π·16·h, multiply 83·3 = 249 and 3/3 = 1
249/ π·16 = h , divide both sides by π·16
1,268.146587 = h, solve
1,268 ≈ h , is rounded to the nearest cm