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AlexFokin [52]
3 years ago
13

what is the measure of the central angle of a circle with a radius 24 ft that intercepts at 10 ft arc? use 3.14 as pie​

Mathematics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

central angle =23.88°

Step-by-step explanation:

Given:Arc length =10ft

           radius= 24ft

To find : central angle

Formula: Arc length = 2πr.\frac{\theta}{360}°

                ⇒{\theta} = \frac{arc length.360}{2{\pi}{r}}

               ⇒ {\theta} = \frac{10(360{\degree})}{2 (3.14)(24)}

                ⇒{\theta}=23.8853503°

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Quadrilateral HJKL ~ Quadrilateral MPNQ<br><br> Which statements must be true
LenKa [72]

Answer:

m∠K =m∠N

HJ/MP=JK/PN

Step-by-step explanation:

The picture of the question in the attached figure

we know that

if two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

<u><em>Verify each statement</em></u>

case a) we have

m∠K =m∠N

The statement is true

Because, angle K and angle N are corresponding angles, and remember that in similar figures corresponding angles are congruent

case b) we have

HJ≅MP

The statement is false

Segment HJ and segment MP are proportional, not congruent

case c) we have

m∠J≅m∠N

The statement is false

Because angle J and angle N are not corresponding angles

case d) we have

HJ/MP=JK/PN

The statement is true

Because, the ratio of its corresponding sides is proportional

so

\frac{HJ}{MP}=\frac{JK}{PN}=\frac{KL}{NQ}=\frac{HL}{MQ}

7 0
3 years ago
Mr. and Mrs. Jones live in a neighborhood where the mean family income is $45,000 with a standard deviation of $9,000. Mr. and M
hichkok12 [17]

Answer:

Jones(20%), Smiths(30%)

Step-by-step explanation:

The relative dispersion of a data set is the ratio of its standard deviation to its arithmetic mean.

Mr. and Mrs. Jones' neighborhood mean family income is $45,000 with a standard deviation of $9,000.

Their Relative Dispersion is given as:

Standard Deviation: Mean

9000:45000

1:5

Expressed as a Percentage: (1/5)x100=20%

The Relative Dispersion of the family incomes in Mr. and Mrs. Jones' neighborhood is 20%

Mr. and Mrs. Smith's neighborhood mean family income is $100,000 and the standard deviation is $30,000.

Their Relative Dispersion is given as:

Standard Deviation: Mean

30000:100000

3:10

Expressed as a Percentage: (3/10)x100=30%

The Relative Dispersion of the family incomes in Mr. and Mrs. Smith's neighborhood is 30%

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Answer:1005

Step-by-step explanation:sorry if I’m wrong I really want a like it would help a lot but I think this answer is right

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