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3 years ago

15

Carmen buys 4 daisies and some roses to make a flower arrangement. The number of daisies is 1/3 of the number of roses that she

buys. How many roses does she buy?

1 answer:

Bumek [7]3 years ago

3 0

Answer:

12

Step-by-step explanation:

$4 / 1/3=4*3/1=4*3=12$

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X + 4y = 4 and x - 4y = 19 help please and show your work

lina2011 [118]

Can you use negative number?

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3 years ago

6<br> 1 point<br> Find the sum of 4y2 - 2y-5 and y2-y+8

gogolik [260]

Answer:

assuming that you want us to add them together here's the answer i got-

5y²−3y+3

Step-by-step explanation:

let us simplify step-by-step-

4y²−2y−5+y²(−y)+8

= 4y²+(−2y)+(−5)+y²+(−y)+8

combining like terms-

=4y²+−2y+−5+-y²+−y+8

=(4y²+y²)+(−2y+−y)+(−5+8)

=5y²+−3y+3

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3 years ago

WRITE a Linear FUNCTION, f, with the given values:<br> f(-4) = -5 and f(2) = -3

Crazy boy [7]

Answer:

answer to the question is A

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3 years ago

People that are smart in geometry reflect figure over line can you guys do this for me in my delta math account pls

san4es73 [151]

Answer:

Uh just count how many boxes/units away a point is away from the line and keep on potting till the whole shape is formed.

Step-by-step explanation:

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3 years ago

Can someone help me with this?<br> Find the roots of -x^2-20=-x^4

Degger [83]

The roots are $x=2 i, x=-2 i, x=\sqrt{5}, x=-\sqrt{5}$

Step-by-step explanation:

The equation is $-x^{2} -20=-x^{4}$

Switch sides, we get,

$-x^{4}=-x^{2} -20$

Adding both sides by 20, we get,

$-x^{4}+20=-x^{2}$

Adding both sides by $x^{2}$ ,

$-x^{4}+x^{2}+20=0$

To solve this equation, let us assume $u=x^{2}$ and $u^{2}=x^{4}$

Thus, rewriting this equation,

$-u^{2} +u+20=0$

Using quadratic formula, we get the value of u.

$\begin{aligned}&u=\frac{-1 \pm \sqrt{1-4(-1)(20)}}{2(-1)}\\&\begin{aligned}&=\frac{-1 \pm \sqrt{1+80}}{-2} \\&=\frac{-1 \pm \sqrt{81}}{-2} \\u &=\frac{-1 \pm 9}{-2}\end{aligned}\end{aligned}$

The variable u has two solutions,

$\begin{aligned}u &=\frac{-1+9}{-2} \\&=\frac{8}{-2} \\u &=-4\end{aligned}$ and $\begin{aligned}u &=\frac{-1-9}{-2} \\&=\frac{-10}{-2} \\u &=5\end{aligned}$

Since, $u=x^{2}$ and $u^{2}=x^{4}$

Thus, substituting the u-values, we get,

$\begin{aligned}u &=x^{2} \\-4 &=x^{2} \\\sqrt{-4} &=\sqrt{x^{2}} \\\pm 2 i &=x\end{aligned}$ and $\begin{aligned}u &=x^{2} \\5 &=x^{2} \\\sqrt{5} &=\sqrt{x^{2}} \\\pm \sqrt{5} &=x\end{aligned}$

Thus, the roots are $x=2 i, x=-2 i, x=\sqrt{5}, x=-\sqrt{5}$

5 0

3 years ago