A=number of seats in section A
B=number of seats in section B
C=number of seats in section C
We can suggest this system of equations:
A+B+C=55,000
A=B+C ⇒A-B-C=0
28A+16B+12C=1,158,000
We solve this system of equations by Gauss Method.
1 1 1 55,000
1 -1 -1 0
28 16 12 1,158,000
1 1 1 55,000
0 -2 -2 -55,000 (R₂-R₁)
0 12 16 382,000 (28R₁-R₂)
1 1 1 55,000
0 -2 -2 -55,000
0 0 4 52,000 (6R₂+R₃)
Therefore:
4C=52,000
C=52,000/4
C=13,000
-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.
A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.
Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
<span>9540000 = 9x1000000 + 5x100000 + 4x10000
= 9x10^6 + 5x10^5 + 4x10^4</span>
Answer: B
Step-by-step explanation:
The equation is:
y
=
5
4
x
−
13
Explanation:
The slope-intercept form of a straight line is
y
=
m
x
+
c
In this case we have a point,
(
x
,
y
)
and the slope,
m
so all we need is a value for
c
.
Substitute into
y
=
m
x
+
c
−
3
=
5
4
(
8
)
+
c
−
3
=
10
+
c
c
=
−
13
