(1 point) Find an equation of the largest sphere with center (5,3,5)(5,3,5) and is contained in the first octant. Be sure that y
1 answer:
Answer:
x^2+y^2+z^2-10x-6y-10z +50 =0
Step-by-step explanation:
Given that a sphere is contained in the first octant
Centre of the sphere is given as (5,3,5)
Since this is contained only in the first octant radius should be at most sufficient to touch any one of the three coordinate planes
When it touches we can get the maximum sphere
We find that y coordinate is the minimum of 3 thus radius can be atmost 3 so that then only it can touch y =0 plane i.e. zx plane without crossing to go to the other octants.
Hence radius =3
Equation of the sphere would be
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The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number
In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number
Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)
Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)
Let X be the number of times the die is rolled
The probability of getting a prime =
Now, the value of
E(X)=∑x.P(x) [ x-> {1, infinity}]
= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)
= 1. + 2.
.
+ 3.
.
+ 4.
.
.
.
.......
Hence, this is the value of E(x)
To learn more about Prime number, here
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