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2 years ago

Sixth grade

Mathematics

1 answer:

marusya05 [52]2 years ago

6 0

Just take $1,557,555 and divide by 3. You should get 519,185 Snacks

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A company launches 4 new products. The market price, in dollars, of the 4 products after a different number of years, x, is show

dem82 [27]

Product 4 after the third year is 27 which is higher than the rest after 3 years.

And because x is raised to the third, the amount would Increase by being raised to the 3rd every year.

The answer is Product 4.

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3 years ago

Evaluate 7- 5p + 3q when p=1 and a=7

irina1246 [14]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4. which describes the relationship between the two trian

Nadya [2.5K]

Answer:

ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.

Step-by-step explanation:

It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.

If a figure is dilated then preimage and image are similar.

If scale factor is between 0 to 1, then preimage is reduction of image.

If scale factor is more that 1, then preimage is enlargement of image.

If scale factor is 1, then preimage is congruent to the image.

We know that

$\frac{3}{4}=0.75$

So,

$0$

Therefore, the ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.

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3 years ago

Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

2 years ago

What is the equation of the line that passes through the point (−8,1) and has a slope of -3/4?

Marrrta [24]

Answer:

y-1=-3/4(x+8)

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept,

y-y1=m(x-x1)

y-1=-3/4(x-(-8))

y-1=-3/4(x+8)

6 0

3 years ago