$({4x}^{3} - {5x}^{2} + 3x) + ( - {2x}^{3} - {x}^{2} + 6x) \\ 2 {x}^{3} - 6 {x}^{2} + 9x = 0 \\ dividing \: by \: x \\ 2 {x}^{2} - 6x + 9 = 0 \\ dividin g\: by \: 2 \\ {x}^{2} - 3x + \frac{9}{2} = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\ {x}^{2} - 3x = - \frac{9}{2} \\ adding \: \frac{1}{2} \times (coefficient \: of \: x) \: whole \: square \\$

On solving the above mentioned equation we get some imaginary values.

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6 0

3 years ago

True or false? Postulates are statements that are accepted without question or justification

ale4655 [162]

True, as a postulate is the assumption of existence.

6 0

3 years ago

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Use the properties of exponents to rewrite the expression (-3yz)(-3yz)(-3yz)(-3yz)

Ipatiy [6.2K]

$\bf (-3yz)(-3yz)(-3yz)(-3yz)\implies (-3yz)^1(-3yz)^1(-3yz)^1(-3yz)^1 \\\\\\ (-3yz)^{1+1+1+1}\implies (-3yz)^4\implies (-3)^4 y^4 z^4\implies 81y^4 z^4$