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Inga [223]
3 years ago
7

Use the compound interest formula to compute the total amount accumulated and the interest earned.

Mathematics
1 answer:
Dovator [93]3 years ago
4 0
A=6,500×(1+0.07÷360)^(360×5)
A=9,223.63

Interest earned
9223.63-6500==2,723.63
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- 2 + 0.8) ÷ (- 1.3) =<br><img src="https://tex.z-dn.net/?f=%20%28%20-%202%20%2B%200.8%29%20%5Cdiv%20%28%201%7D%5E%7B2%7D%20%20-
Nookie1986 [14]
(-2 + 0.8) ÷ (1²-1.3) =

(-1.2) ÷ (1-1.3)

(-1.2) ÷ (-0.3)

= 4
6 0
3 years ago
For EASY BRAINLIEST!!! <br><br> Answer:<br> A.<br> B.<br> C.<br> D. <br><br> On both questions
tekilochka [14]

Answer:

8a) 3x

8b) 3 × x

8c) (2/3)x

8d) x/2

8e) 1/x

9a) 4x - 7

9b) x + 1/x

9c) 5(x + 2)

9d) x/(x + 4)

9e) (x/8) + x

4 0
3 years ago
A credit card company applies a 6% fee on all transactions under $10. You purchased coffee for $4.80. What fee amount will be ap
Romashka [77]

Answer:

$5.08

Step-by-step explanation:

Step one:

given data

We are told that a credit card company applies a 6% fee on all transactions under $10

since the cost of coffee bellow $10 that is $4.80, the 6% fee is applicable

so

=6% of 4.80

=6/100*4.80

=0.06*4.8

=$0.288

Step two:

the total fee will be

=0.288+4.80

= $5.08

7 0
3 years ago
Can someone help me please i need help..! problem: x/-8+15&gt;23
bazaltina [42]

Answer:

X<-64

Step-by-step explanation:

3 0
3 years ago
Factoring trinomials
Tcecarenko [31]

c^22c^2 + 13c +21 \\4c^2 + 13(2)c + 42\\(2c + 6)(2c+7)\\(c+3)(2c+7)


This is a way to factoring trinomials (there exist different equivalent methods).

Multiply the trinomial but the term accompanying  c^2. This is the second line. Then, you could take the square of the 4c^2, ant try to create a factor () () that will correspond to the expression in the second line. That is, we want 4c^2 + 13(2) c + 42 = (2c + ?) (2c + ?)

In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have (2c + 6) (2c +7)

The last step is divide by the number that we multipy in the first step.

4 0
3 years ago
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