What is the equation ?

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

$y=1/3x$

Step-by-step explanation:

It's positive, and it goes up once for every three times it goes to the right.

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You are given the exponential function g(x)=3^x. Which ootion below gives the formula for the new function h created by stretchi

Citrus2011 [14]

Answer:

h(x) = 3^(x + 1)

Step-by-step explanation:

The exponential function is;

g(x) = 3^(x)

Now, in transformation of exponential functions of say f(x) = b^(x), when the new function g(x) is created by stretching by a factor of say c along the y-axis, we have;

g(x) = c•b^(x)

In this question, we are told it is stretched by a factor of 3 along the y-axis.

Thus, new function h is;

h(x) = 3 × 3^(x)

Using law of indices, we have;

h(x) = 3^(x + 1)

7 0

3 years ago

A bookstore can purchase several calculators for a total cost of $120. If each calculators cost $1 less, the bookstore could pur

Tresset [83]

$x-number\ of\ calculators\ sold\ in\ regular\ price\\\\
y-\ \ first\ price\\\\
(y-1)\ \ -second\ price\\\\x=\frac{120}{y}\\
x+10=\frac{120}{y-1}\\\\Substitude\ x=\frac{120}{y}\ into\ the\ second\\\\\
\frac{120}{y}+10=\frac{120}{y-1}\ \ |-\frac{120}{y-1}-10\\\\
\frac{120}{y}-\frac{120}{y-1}=-10\\\\Make\ a\ common\ denominator\\\\
\frac{120(y-1)}{y(y-1)}-\frac{120y}{(y-1)y}=-10
\frac{120y-120)}{y(y-1)}-\frac{120y}{(y-1)y}=-10\\\\
\frac{120y-120-120y}{y(y-1)}=-10$ <u /> $Assumptions:\\y \neq 0\ \ \ and\ \ y \neq 1\\\\ \frac{-120}{y(y-1)}=-10\ \ \ | *y(y-1) \\\\
-120=-10y(y-1)\\\\
-120=-10y^2+10y\\\\
10y^2-10y-120=0\ \ \ |:10\\\\
y^2-y-12=0\\\\Factor\ equation\\\\ y^2+3y-4y-12=0\\\\
(y-4)(y+3)=0\\\\Solutions:\ \ y=4\ \ and\ \ y=-3$