Question

If (a/b) =(9/7)^-3 ÷(3/7)^1, then find the value of (a/b)^2​

Answer 1

Answer:

decimal = 1.20527

Step-by-step explanation:

$\frac{a}{b} = (\frac{9}{7})^{-3} \div (\frac{3}{7})^1$

  $=(\frac{7}{9})^3 \times \frac{7}{3}$

$(\frac{a}{b})^2 = ((\frac{7}{9})^3)^2 \times (\frac{7}{3})^2$

      $= \frac{7^6 \times 7^2}{9^6 \times 3^2}\\\\= \frac{7^8}{9^6 \times 9}\\\\=\frac{7^8}{9^7}\\\\=\frac{7^7 \times 7}{9^7}\\\\= 7 \times \frac{7^7}{9^7}\\\\= 7 \times (\frac{7}{9})^7$

      $=\frac{5764801}{4782969}$