90 is the LCM of 30 and 45
As anoutline, angles O and Q are inscribed angles which are measured by one-half of its intercepted arc.
angle O = 1/2 arc RQP
angle Q = 1/2 arc ROP
so arcs RQP and ROP together make up the entire circle which has 360 degrees.
so angles O and Q is 1/2 (360) = 180 degrees (supplementary angles).
-1(2x+3)-2(x-1)
-2x-3-2x+2
-4x-1
Answer:
i. <DCB = 
ii. Sin of <DCB = 0.8
Step-by-step explanation:
Let <DCB be represented by θ, so that;
Sin θ = 
Thus from the given diagram, we have;
Sin θ = 
= 0.8
This implies that,
θ =
0.8
= 53.1301
θ = 
Therefore, <DCB =
.
So that,
Sin of <DCB = Sin 
= 0.8
Sin of <DCB = 0.8