Answer:
Commutative
Please, mark as brainliest
Answer:
4x+2h
Step-by-step explanation:
The average rate of change of a continuous function,
f
(
x
)
, on a closed interval
[
a
,
b
]
is given by
f
(
b
)
−
f
(
a
)
b
−
a
So the average rate of change of the function
f
(
x
)
=
2
x
2
+
1
on
[
x
,
x
+
h
]
is:
A
r
o
c
=
f
(
x
+
h
)
−
f
(
x
)
(
x
+
h
)
−
(
x
)
=
f
(
x
+
h
)
−
f
(
x
)
h
...
.
.
[
1
]
=
2
(
x
+
h
)
2
+
1
−
(
2
x
2
+
1
)
h
=
2
(
x
2
+
2
x
h
+
h
2
)
+
1
−
2
x
2
−
1
h
=
2
x
2
+
4
x
h
+
2
h
2
−
2
x
2
h
=
4
x
h
+
2
h
2
h
=
4
x
+
2
h
Which is the required answer.
Additional Notes:
Note that this question is steered towards deriving the derivative
f
'
(
x
)
from first principles, as the definition of the derivative is:
f
'
(
x
)
=
lim
h
→
0
f
(
x
+
h
)
−
f
(
x
)
h
This is the function we had in [1], so as we take the limit as
h
→
0
we get the derivative
f
'
(
x
)
for any
x
, This:
f
'
(
x
)
=
lim
h
→
0
4
x
+
2
h
=
4
x
In time period of 1980-1988 the rate of ticket price is $0.2 per year
Between time period 1989-1993 there is constant rate.
Between year 1994-2011 the increase in rate is same $0.2 per year
The graph could be divided up into three different periods of relatively consistent ticket price change: The years 1980 – 1988, 1989 – 1993 and 1994 – 2011.
<h3>What is Statistic?</h3>
The statistic is the study of mathematics which deal with relations between comprehensive data.
The graph is not available, in the question, so the graph could be as attached
For period 1980-1988
rate of change = 4.2-2.8/ 8 = 0.2
In time period of 1980-1988 the rate of ticket price is $0.2 per year
for period 1989-92 there is a straight line so,
Between time period 1989-1993 there at constant rate.
For period, 1994-2011
rate of change = 4.4-8/17 = 0.2
Between year 1994-2011 the increase in rate is same $0.2 per year
Thus, for the 3 Time period we have rate of change in ticket price is $0.2 per year, no change in ticket price, $0.2 per year respectively.
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