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3 years ago

Need helpNo web linkSimplify

Mathematics

2 answers:

Damm [24]3 years ago

8 0

x^( 2a - b ) + ( 2b + c ) + ( 2c + a ) =

x^2a + a + 2b - b + 2c + c =

x^3a - b + 3c

saveliy_v [14]3 years ago

3 0

Step-by-step explanation:

Simply add the exponents after combining the bases

${x}^{2a - b} \times {x}^{2b - c} \times {x}^{2c + a}$

$= {x}^{2a - b + 2b - c + 2c + a}$

$= {x}^{3a + b + 3c}$

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3 years ago

Read 2 more answers

Which graph represents the solution to the given system ? Y=- 6X - 2Y +2=- 6X

Nonamiya [84]

Answer: The graph is attached.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

Given the first equation:

$y=- 6x - 2$

You can identify that:

$m=-6\\b=-2$

By definition, the line intersects the x-axis when $y=0$ . Then, subsituting this value into the equation and solving for "x", you get that the x-intercept is:

$0=- 6x - 2\\\\2=-6x\\\\x=-\frac{1}{3}\\\\x=-0.333$

Now you can graph it.

Solve for "y" from the second equation:

$y +2=- 6x\\\\y=-6x-2$

You can identify that:

$m=-6\\b=-2$

Notice that the slopes and the y-intercepts of the first line and the second line are equal; this means that they are exactly the same line and the System of equations has<u> Infinitely many solutions.</u>

See the graph attached.