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3 years ago

Is this right idk but i need work fir it

Mathematics

1 answer:

bija089 [108]3 years ago

7 0

Answer:

The answer is C 5/4

Step-by-step explanation:

When lines are parallel and you know there is a scalar factor, make the ratio by putting the original over the dilation 15:12 or 15/12 this is the ratio and after you need to reduce by dividing by the greatest common factor. 15 and 12's GCF is 3 so (15/3)/(12/3) = 5/4.

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PLEASE HELP NOBODY WILL HELP ME I WILL GIVE BRAINLIEST

d1i1m1o1n [39]

Answer:

See below

Step-by-step explanation:

Let the number of Payday be p and Baby Ruth be b

Then sub of the candy bars:

p + b = 220

Payday candy bars worth ⇒ $2p
Baby Ruth candy bars worth ⇒ $3b
Total ⇒ $600

1. Required equations:

p + b = 220
2p + 3b = 600

2. Solving by substitution:

p = 220 - b, consider it in the second equation

2(220 - b) + 3b = 600
660 - 2b + 3b = 600
660 + b = 600
b = 660 - 600
b = 60

60 Baby Ruth candy bars sold

4 0

2 years ago

A piece of pipe is 303/4 inches long. If five pieces, each 41/3 inches long, are cut from the pipe, how many inches of pipe rema

galina1969 [7]

So, what is the total lenght of the pieces that wer cut off?

we multiply the lenght by the number:

4 $\frac{1}{3}$ *5=20+ $\frac{5}{3}$ =21 $\frac{2}{3}$

and we subtract this from the original pipe, that is

30 $\frac{3}{4}$ -21 $\frac{2}{3}$

we need to bring the two fractions to the same denominator (by multiplying the fraction art in the first by 3 and 4 the second):

30 $\frac{9}{12}$ -21 $\frac{8}{12}$ =9 $\frac{1}{12}$

so the correct answer is D!

3 0

3 years ago

Jeremy makes a drawing of a walkway shaped like three rectangles. The total area of the walkway is 24 square meters. What is the

nadya68 [22]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground. a.Find

Lyrx [107]

A.)
s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]

b.)
s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \]

4 0

3 years ago

1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h

alina1380 [7]

Answer: $(g,h)=(-2,2)$