9514 1404 393
Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
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<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
In a triangle, the midline joining the midpoints of two sides is parallel to the third side and half as long
2(5x+2) = 3x + 32
10x + 4 = 3x + 32
10x - 3x = 32 - 4
7x = 28
x = 28/7
x = 4
The length of the midsegment = 5x+2 = 5·4 + 2 = 22
Answer:
the graph is as illustrated above
The absolute value of x is shifting 3 units up
Shifted up 8 and right 7
answer
B. second option
I think the answer is 360
