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3 years ago

Can someone tell me what x= to and y=?

Mathematics

1 answer:

jeka57 [31]3 years ago

3 0

Answer:

x = 112

y = 76

Step-by-step explanation:

x + 68 = 180

x = 180 - 68

x = 112

y = 76 (Because of alternate interior angles)

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(2a-b)^2 -4(2a-b) -13 =

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Solve <img src="https://tex.z-dn.net/?f=-2x%5E2%20%2B3x%20-%209%20%3D%200" id="TexFormula1" title="-2x^2 +3x - 9 = 0" alt="-2x^2

MArishka [77]

Answer:

$x= \frac{3-3\sqrt{7}i }{4}$ and $x= \frac{3+3\sqrt{7}i }{4}$

Step-by-step explanation:

We have to solve the given equation - 2x² + 3x - 9 = 0

To solve the equation given above we have to factorize the left-hand side of the equation.

But it can not be factorized. So, use the Sridhar Achaya formula.

Therefore, $x= \frac{-3 + \sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)}$ and $x= \frac{-3 -\sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)}$

So, $x= \frac{3-3\sqrt{7}i }{4}$ and $x= \frac{3+3\sqrt{7}i }{4}$ {Where $i=\sqrt{-1}$ }

Therefore, the solutions are imaginary numbers. (Answer)

Note: The Sridhar Acharya Formula gives if ax² + bx + c = 0, then the roots of the equation are $x = \frac{-b + \sqrt{b^{2}-4ac } }{2a}$ and $x = \frac{-b - \sqrt{b^{2}-4ac } }{2a}$ .

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