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3 years ago

0.5y+4=7 can some one please help me with this problem it will be great.

Mathematics

2 answers:

Brut [27]3 years ago

7 0

Answer:

If u have to find the value of y it is y=6

Step-by-step explanation:

Rainbow [258]3 years ago

5 0

Answer:

Step-by-step explanation:

0.5y+4=7

0.5y=7-4

0.5÷0.5y=3÷0.5

y=6

( if they want tha value of y)

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1/3 of 9 is 3<br> How can you figure out these problems

gtnhenbr [62]

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3 years ago

List all rational roots that are possible according to the rational zero theorem. x^3-5x^2-9x+45=0

Lina20 [59]

-3, 3, 5.

https://www.wolframalpha.com/input/?i=%28x%5E3%29-%285x%5E2%29-9x%2B45%3D0

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3 years ago

The sum of two consecutive integers is 85. What are those two<br> integers?

chubhunter [2.5K]

Answer:

41 and 42

Step-by-step explanation:

Let the integers be x and x + 1

=> x + x + 1 = 85

=> 2x + 1 = 85

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7 0

2 years ago

<img src="https://tex.z-dn.net/?f=50%20%2B%20%2840%20-%2015%29%20%5Cdiv%206" id="TexFormula1" title="50 + (40 - 15) \div 6" alt=

IgorLugansk [536]

Answer:

12.5

Step-by-step explanation:

first you do the one in the 40-15 then you add 50 the you divide by 6

8 0

3 years ago

Read 2 more answers

Keiko has seven colors of lanyard. She uses three different colors to make a keychain. How many different combinations can she c

AleksAgata [21]

Combination = doesn't matter what order
Permutation = order matters

There are <u>two</u> methods to work out combinations.

Method 1 List out possibilities
123 124 125 126 127 134 135 136 137 145 146 147 156 157 167
234 235 236 237 245 246 247 256 257 267
345 346 347 356 357 367
456 457 467
567

For a total of 35 combinations.

Method 2 Use a formula.
It's a rather complicated one, so only use it if you have a lot of possibilities.

$\frac{n!}{r!(n-r)!} = \frac{7!}{3!(7-3)!} = \frac{7!}{3!*4!} = \frac{7*6*5*4*3*2*1}{3*2*1*4*3*2*1} = \frac{7*6*5}{3*2*1}=\frac{210}6=35$

(n is the number of choices, r is the amount you choose, and ! is a function that multiplies together all numbers down to 1)

7 0

4 years ago