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Marta_Voda [28]
3 years ago
5

The value of a school bus reduces from $512000 to $343000in 3 years. Find the

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>

Step-by-step explanation:

<u>Rate of Depreciation</u>

If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.

It can be calculated as:

\displaystyle R=\frac{P-Q}{t}

It can also be expressed as a percentage, dividing the previous value by P.

The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:

\displaystyle R=\frac{512,000-343,000}{3}

\displaystyle R=\frac{169,000}{3}

R = 56,333 $/year

Expressed as a percentage:

R = 56,333 / 512,000 = 0.11

R = 11%/year

The uniform rate of depreciation is $56,333 per year, or 11% per year.

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umka21 [38]

If each person got 1/6 then there is still 2/6 left over, =1/3. In fraction strips, we would do

                  1

  1/3         1/3        1/3                                                                 1/3

1/6 1/6   1/6 1/6  1/6 1/6 for the overall tomato and then  1/6 1/6  for the remaining piece of the tomato.

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8 0
3 years ago
How do I find the answers
jasenka [17]

Answer:

3. They're adding by 5 so,

Step-by-step explanation:

6 0
3 years ago
LM is a perpendicular bisector of NP The length of LN is 12w +7, and the length of LP is 15w 5. What is the length of LN?
Mazyrski [523]

Answer:

LN = 55

Step-by-step explanation:

Given

LN = 12w + 7

LP = 15w - 5

Required

Determine LN

Since LM is a bisector, then we have:

LP = LN (See attachment for illustration)

15w - 5 = 12w + 7

Collect Like Terms

15w - 12w = 5 +7

3w = 12

Solve for w

w = 12/3

w = 4

LN is calculated as thus:

LN = 12w + 7

Substitute 4 for w

LN = 12 * 4 + 7

LN = 48 + 7

LN = 55

8 0
2 years ago
Find the solution of y = 3x + 3 for x = –3.
mixas84 [53]

Answer:

<h2>(-3,-6)</h2>

Step-by-step explanation:

hope it help you

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3 0
2 years ago
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The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did
Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

P(A \, and \, B)= P(A)\times  P(B\left |  \right A )

From the options, we have;

P(fatigue \left |  \right drug) = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×P(fatigue \left |  \right drug)  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0
2 years ago
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