The value of a school bus reduces from $512000 to $343000in 3 years. Find the
1 answer:
Answer:
<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>
Step-by-step explanation:
<u>Rate of Depreciation</u>
If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.
It can be calculated as:
It can also be expressed as a percentage, dividing the previous value by P.
The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:
R = 56,333 $/year
Expressed as a percentage:
R = 56,333 / 512,000 = 0.11
R = 11%/year
The uniform rate of depreciation is $56,333 per year, or 11% per year.
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Answer:
C. Both Carter and Demi are correct and would get the same answer.
Step-by-step explanation:
Here, the given polynomial is :
The given monomial :
Now, according to the given question:
Dividend = P(x), Divisor = Q(x)
Now, Carter divide P(x) by Q (x) with LONG DIVISION METHOD.
If we divide P(x) by Q(x) by Long division, we get:
Also, if Demi divides each term of P(x) by The given monomial (2x) , we get:
⇒In both the case, R(X)Quotient is SAME.
Hence, Both Carter and Demi are correct and would get the same answer.
The ratio of life expectancy to gestation period is greatest at point (A) A.
<h3>What is life expectancy?</h3>- Life expectancy is a statistical measure of how long an organism is expected to live based on its birth year, current age, and other demographic factors such as gender.
- The most commonly used metric is life expectancy at birth (LEB), which has two definitions.
To find the labeled points, which represent the animal for which the ratio of life expectancy to gestation period is greatest:
- The graph below shows life expectancy on the y-axis and gestation period on the x-axis.
- The life expectancy to gestation period ratio for point A is 7/22.5 = 14/45.
- For point B, the ratio is 8/45.
- Because the y coordinate is greater at Y than at X, which has the same x coordinate, we only consider the ratio at D, which is 10/51.
- Since 14/45 > 8/45, we only have to compare 14/45 and 10/51.
- So, 14 × 51 = 714 and 45 × 10 = 450.
- Then, 14/45 > 10/51.
Therefore, the ratio of life expectancy to gestation period is greatest at point (A) A.
Know more about life expectancy here:
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The correct question is given below:
Of the labeled points, which represent the animal for which the ratio of life expectancy to gestation period is greatest?
A) A
B) B
C) C
D) D
