Please help! im begging!

Mathematics

1 answer:

Dafna1 [17]2 years ago

7 0

Don't trust me but it's probably the first one. Just using context clues

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May someone help me find A H AND K ?

NNADVOKAT [17]

Answer:

a = -2

h = -1

k = -6

Step-by-step explanation:

This is called the vertex form of a quadratic:

y = a(x – h)2 + k

To arrive at the answer, simply locate where each variable would be in place of the number.

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7 0

3 years ago

Sample Work Help Needed! Please answer these questions and show the steps used to solve them. NO DECIMAL ANSWERS (except on thre

anygoal [31]

1. Using the exponent rule (a^b)·(a^c) = a^(b+c) ...

$\left(-2x^3y^4\right)\left(5x^9y^{-2}\right)=(-2)(5)\left(x^{(3+9)}y^{(4-2)}\right)\\\\=-10x^{12}y^{2}$

Simplify. Write in Scientific Notation

2. You know that 256 = 2.56·100 = 2.56·10². After that, we use the same rule for exponents as above.

$8 \left(32\times 10^{11}\right)=(8)(32)\times 10^{11}=256\times 10^{11}=2.56\times 10^{13}$

3. The distributive property is useful for this.

(3x – 1)(5x + 4) = (3x)(5x + 4) – 1(5x + 4)

... = 15x² +12x – 5x –4

... = 15x² +7x -4

4. Look for factors of 8·(-3) = -24 that add to give 2, the x-coefficient.

-24 = -1×24 = -2×12 = -3×8 = -4×6

The last pair of factors adds to give 2. Now we can write

... (8x -4)(8x +6)/8 . . . . . where each of the instances of 8 is an instance of the coefficient of x² in the original expression. Factoring 4 from the first factor and 2 from the second factor gives

... (2x -1)(4x +3) . . . . . the factorization you require

8 0

3 years ago

What is the value of 5^3i^9?

Yakvenalex [24]

Answer:

$\displaystyle 125^i$