Answer:


Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:
We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.
Step-by-step explanation:
We have the following info given:
represent the sampel mean for the age of customers
represent the population standard deviation
represent the sample size selected
We want to test if the mean age of her customers is over 35 so then the system of hypothesis for this case are:
Null hypothesis: 
Alternative hypothesis 
The statistic for this case is given by:

And replacing the data given we got:

We can calculate the p value since we are conducting a right tailed test like this:

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:
We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.
Answer: y=−1 or y=2
Step-by-step explanation:
Step-by-step explanation:
Like Terms: Terms that have identical variable parts (same variable(s) and same exponent(s)). When simplifying using addition and subtraction, you combine “like terms” by keeping the "like term" and adding or subtracting the numerical coefficients.
Answer:
Assume you will invest fixed amount x at the starting of each month
S(12): (1.00625x)*(1.00625^(12)-1)/(1.00625-1) = 2000
x=160
you will invest fixed amount 160 at the starting of each month and get 2000 at the end of the year ,which compounded 7.5% monthly.
how much will you have invested at the end of the first year ?
160*12=1920
(A)
P(<em>X</em> < 61.25) = P((<em>X</em> - 55.4)/4.1 < (61.25 - 55.4)/4.1)
… ≈ P(<em>Z</em> ≤ 0.1427)
… ≈ 0.5567
(B)
P(<em>X</em> > 46.5) = P((<em>X</em> - 55.4)/4.1 > (46.5 - 55.4)/4.1)
… ≈ P(<em>Z</em> > -2.1707)
… ≈ 1 - P(<em>Z</em> ≤ -2.1707)
… ≈ 0.9850