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nordsb [41]
3 years ago
14

What is the equivalent ratio of 1/3​

Mathematics
2 answers:
Sonbull [250]3 years ago
7 0
2:6
That fraction is a number that stand the fraction
sp2606 [1]3 years ago
3 0

1 : 3         2 : 6         3 : 9       4 : 12         5 : 15

6 : 18 7 : 21 8 : 24 9 : 27 10 : 30

11 : 33 12 : 36 13 : 39 14 : 42 15 : 45

16 : 48 17 : 51 18 : 54 19 : 57 20 : 60

21 : 63 22 : 66 23 : 69 24 : 72 25 : 75

26 : 78 27 : 81 28 : 84 29 : 87 30 : 90

31 : 93 32 : 96 33 : 99 34 : 102 35 : 105

36 : 108 37 : 111 38 : 114 39 : 117 40 : 120

41 : 123 42 : 126 43 : 129 44 : 132 45 : 135

46 : 138 47 : 141 48 : 144 49 : 147 50 : 150

51 : 153 52 : 156 53 : 159 54 : 162 55 : 165

56 : 168 57 : 171 58 : 174 59 : 177 60 : 180

61 : 183 62 : 186 63 : 189 64 : 192 65 : 195

66 : 198 67 : 201 68 : 204 69 : 207 70 : 210

71 : 213 72 : 216 73 : 219 74 : 222 75 : 225

76 : 228 77 : 231 78 : 234 79 : 237 80 : 240

81 : 243 82 : 246 83 : 249 84 : 252 85 : 255

86 : 258 87 : 261 88 : 264 89 : 267 90 : 270

91 : 273 92 : 276 93 : 279 94 : 282 95 : 285

96 : 288 97 : 291 98 : 294 99 : 297 100 : 300

<em>You don't need to write all of them, only a few or how many do you want...</em>

<h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>

<em>by a random Romanian guy</em>

<em></em>

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MArishka [77]

Answer:

ok

Step-by-step explanation:

9+10=21

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Answer:

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There are 50 animals in a shelter. Three hundred vehicles are parked in a parking garage. Seventy of the vehicles are midsized c
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230

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3 0
3 years ago
Examine the diagram at right. The smaller triangle (inside of the larger triangle) is similar to larger triangle. How can you so
olchik [2.2K]

As the exercise says, the triangles are similar. So, we can set up proportions between correspondent sides.

In order to solve for x we can set up the proportion between the horizontal and vertical sides:

28\div 11.2 = 27+x \div x

Solving this proportion for x implies x=18

Now you can solve for m and p using the pythagorean theorem, because both triangles are right:

m = \sqrt{18^2+11.2^2} =21.2

Then, we know that the hypothenuse of the big triangle is m+p, so we have

m+p=\sqrt{(18+27)^2+28^2} = 53

which implies

p = 53-p = 53-21.2=31.8

6 0
3 years ago
For the problem, use the discriminant to determine the number of real solutions for the equation. Then, find the solutions and c
Ksivusya [100]

Answer:

Discriminant = 55.2 > 0 -> 2 real solutions

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

Step-by-step explanation:

To find the time when the ball will reach the height of 2 meters, we just need to use the value of h = 2 in the equation given. So, we have that:

−4.9t^2 − 4t + 4 = 2

−4.9t^2 − 4t + 2 = 0

For this equation, we have the constants a = -4.9, b = -4 and c = 2. So the discriminant Delta is:

Delta = b^2 - 4ac = 16 + 39.2 = 55.2

sqrt(Delta) = 7.4297

As Delta > 0, we have 2 real solutions

t1 = (-b + sqrt(Delta)) / 2a = (4 + 7.4297) / (-9.8)  = -1.1663 s

t2 = (-b - sqrt(Delta)) / 2a = (4 - 7.4297) / (-9.8)  = 0.35 s

Number of real solutions: 2

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

8 0
3 years ago
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