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FromTheMoon [43]
3 years ago
8

Mary has a cone that has a radius of 5cm and height of 10cm. James has a square pyramid with base length of 10cm and height of 5

cm. Which solid has a larger volume? Explain.
Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer: The cone has a larger volume.

Step-by-step explanation:

Volume of a cone = ⅓πr²h

where, radius = 5cm

height = 10cm

Volume = ⅓ × 3.142 × 5² × 10

Volume of cone = 261.83cm³

Volume of square pyramid = A(h/3)

where, A = 10 × 10 = 100cm²

Volume = 100 × (5/3)

Volume of square pyramid = 166.67cm³

Therefore, the cone has a larger volume.

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A rectangle measures 2 4/ 5 inches by 1 1/ 5 inches. What is its area?
AlexFokin [52]

[ Answer ]

\boxed{3\frac{9}{25} }

[ Explanation ]

Area Of Rectangle: Length * Width

2 4/5 * 1 1/5

=======================

Convert Fractions Into Mixed Numbers:

2 4/5 = 14/5

1 1/5 = 6/5

Multiply Across:

14 * 6

5 * 5

= 84/ 25

Simplify:

3 9/25

\boxed{[ \ Eclipsed \ ]}

4 0
3 years ago
Whats is the 39th triangular number
aleksandr82 [10.1K]

Answer:

The 39th triangle number is 780

7 0
3 years ago
In the bleachers at the basketball game, 1/4 of the fans are adult men,and 5/12 are adult women. What fraction of the fans are a
Vera_Pavlovna [14]
4/12 of the fans are kids because 1/4 can be multaplied by 3 to get 3/12
3 0
3 years ago
The equation represents the proportional
zloy xaker [14]

Answer:

No, more than one hamburger was sold

5 0
3 years ago
The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So
tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

7 0
3 years ago
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