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3 years ago

Solve for x:

Mathematics

2 answers:

Mkey [24]3 years ago

7 0

Answer is...

-abx+a^2/x

Anna71 [15]3 years ago

4 0

Answer:

Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring. While factoring may not always be successful, the Quadratic Formula can always find the solution.

The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.

You might be interested in

In a study to establish the absolute threshold of hearing, 80 male college freshmen were each seated in a soundproof room and a

Norma-Jean [14]

Answer:

Step-by-step explanation:

Hello!

To study the threshold of hering the researcher took a random sample of 80 male college freshmen.

The students underwent an audiometry test where a tome was played and they had to press a button when they detected it. The researcher recorded the lowest stimulus level at which the tone was detected obtaining a sample mean of X[bar]= 22.2 dB and a standard deviation of S= 2.1 dB

To estimate the population mean, since we don't have information about the variable distribution but the sample size is greater than 30, you can use the approximation of the standard normal distribution:

X[bar] ± $Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }$

Where the semiamplitude or margin of error of the interval is:

d= $Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }$

Using a 95% level $Z_{0.975}= 1.965$

d= 1.965 * $\frac{2.1}{\sqrt{80} }$

d= 0.46

The point estimate of the population mean of the threshold of hearing for male college freshmen is X[bar]= 22.2 db

And the estimation using a 95%CI is [21.74;22.66]

I hope this helps!

8 0

3 years ago

A book that cost $58 is now increased by 25 what is the new cost

Dennis_Churaev [7]

Answer:

the new cost is 83

Step-by-step explanation:

58 plus 25 is 83

3 0

2 years ago

Find the major axis for the ellipse <br> x² + 16y2-96y + 128 = 0

Softa [21]

The major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

To answer the question, we need to write it in the standard form of the equation of an ellipse

<h3>Equation of an ellipse</h3>

The equation of an ellipse centered at (h,k) is

(x - h)²/a² + (y - k)²/b² (1) where a > b and the major axis is parallel to the x axis

Given x² + 16y² - 96y + 128 = 0, we convert it into the standard equation of an ellipse.

So, x² + 16y² - 96y + 128 = 0

Dividing through by 16, we have

x²/16 + 16y²/16 - 96y/16 + 128/16 = 0/16

x²/16 + y² - 6y + 8 = 0

Completing the square in y by adding and subtracting (-6/2)² = (-3)²

x²/16 + y² - 6y + (-3)² - (-3)² + 8 = 0

x²/16 + (y - 3)² - 9 + 8 = 0

x²/16 + (y - 3)² - 1 = 0

x²/16 + (y - 3)² = 1

x²/4² + (y - 3)²/1² = 1 (2)

Comparing equations (1) and (2), we have that a = 4 and b = 1.

Since a = 4 > b = 1, the major axis for the ellipse is the x-axis

So, the major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

Learn more about ellipse here:

brainly.com/question/26679189

#SPJ1

8 0

2 years ago

How does finding the greatest common factor help you to solve real world problem

Mashcka [7]

Greatest Common Factors (GCF) can help you in real life problems with fractions and measuring things. Below is a real life example.

Let's say you want to send cookies into one of two classes and want to make sure you have an even number per student. You know that one class has 8 students and the other has 10 students. How many cookies do you make?

Answer: All you have to do is figure out the biggest number that goes into each number equally (division). In this case the answer would be 2.

If i helped please comment below smiley And i hope i helped you!

4 0

3 years ago

The admission fee at fun park is $13 for adults and $9 for children. On a certain day, 940 people entered the park and $10,148 w

siniylev [52]

The answer is 518 children attended the fun park hope this helps

7 0

3 years ago

Read 2 more answers